java ElasticSearch es 聚合排序等

序言:

        近來一直在javaAPI對ES數據進行統計分析, 中間也遇到不少問題, 本篇文章只針對聚合過程中的排序方法進行總結

例如:select  avg(age) as avg_age from table group by gender;

 

聚合的兩種排序方式

       1. 按組內字段排序: 分組後按組內數據某個字段進行排序

       2. 按聚合後指標排序: 分組聚合後按照聚合後的某個新指標字段進行排序

 

案例:

1. 按組內字段排序

AggregationBuilder aggregation =
    AggregationBuilders
        .terms("agg").field("gender")
        .subAggregation(
            AggregationBuilders.topHits("top")
                .explain(true)
                .size(1)
                .from(10)
                .sort("sortFiled", SortOrder.ASC)
        );
輸出

import org.elasticsearch.search.aggregations.bucket.terms.Terms;
import org.elasticsearch.search.aggregations.metrics.tophits.TopHits;
 
// sr is here your SearchResponse object
Terms agg = sr.getAggregations().get("agg");
 
// For each entry
for (Terms.Bucket entry : agg.getBuckets()) {
    String key = entry.getKey();                    // bucket key
    long docCount = entry.getDocCount();            // Doc count
    logger.info("key [{}], doc_count [{}]", key, docCount);
 
    // We ask for top_hits for each bucket
    TopHits topHits = entry.getAggregations().get("top");
    for (SearchHit hit : topHits.getHits().getHits()) {
        logger.info(" -> id [{}], _source [{}]", hit.getId(), hit.getSourceAsString());
    }
}
2. 按聚合後指標排序

 

 import org.elasticsearch.search.aggregations.BucketOrder;
 doc_count以遞增的方式

 AggregationBuilders
    .terms("genders")
    .field("gender")
    .order(BucketOrder.count(true))
按升序方式按字母順序按順序排序 

 AggregationBuilders
    .terms("genders")
    .field("gender")
    .order(BucketOrder.key(true))
按聚合名稱標識對桶進行排序 

 AggregationBuilders
    .terms("genders")
    .field("gender")
    .order(BucketOrder.aggregation("avg_height", false))
    .subAggregation(
        AggregationBuilders.avg("avg_height").field("height")
    )
 按多個聚合指標對桶進行排序

 AggregationBuilders
    .terms("genders")
    .field("gender")
    .order(BucketOrder.compound( // in order of priority:
        BucketOrder.aggregation("avg_height", false), // sort by sub-aggregation first
        BucketOrder.count(true))) // then bucket count as a tie-breaker
    .subAggregation(
        AggregationBuilders.avg("avg_height").field("height")
    )
參考:https://www.elastic.co/guide/en/elasticsearch/client/java-api/current/_bucket_aggregations.html 
--------------------- 
作者：tiansheng1225 
來源：CSDN 
原文：https://blog.csdn.net/tiansheng1225/article/details/82661577 
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