如果 a+b+c=1000,且a^2 + b^2 = c^2(abc爲自然數,如何求出所有可能的組合
import time
start = time.time()
for a in range(1001):
for b in range(1001):
for c in range(1001):
if a + b + c == 1000 and a**2 + b**2 == c**2:
print(a,b,c)
end = time.time()
detla = end - start
print(detla)