求一元二次方程 ax^2 bx c=0ax2 bx c=0 的解

請定義一個函數quadratic(a, b, c)，接收3個參數，

返回一元二次方程 ax^2+bx+c=0ax2+bx+c=0 的兩個解。

#!/usr/bin/python3

import math
def quadratic(a, b, c):
	if not isinstance(a, (int, float))and isinstance(a, (int, float)) and isinstance(a, (int, float)):
		raise TypeError("a or b or c must be a number")
	d = int(b) ** 2-(4*int(a)*int(c))
	if a == 0:
		if b == 0:
			if c == 0:
				return"方程根爲全體實數"
			else:
				return "a can‘t be 0,該方程沒有實數解"
		else:
			x1 = -c/b
			x2 = x1
			return x1, x2
	else:
		if d < 0:
			return "該方程沒有實數解"
		elif d == 0:
			x1 = -b/(2*a)
			x2 = x1
		else:
			x1 = (-b+math.sqrt(d))/(2*a)
			x2 = (-b-math.sqrt(d))/(2*a)
		return (x1,x2)


a1 = input("a=",)
b1 = input("b=",)
c1 = input("c=",)
print("ax^2+bx+c=0的解爲：", quadratic(a1, b1, c1))