Map快速轉換JSon 格式方法和完整的jar

最近在搞java後臺。寫一些測試Servlet接口，所以避免不了的是一些JSon數據的操作。因爲我們前臺最希望的數據返回都是已json格式返回的。其中我們最常用的就是返回結果是自定義的一些map集合，所以我們想要快速轉換成JSON格式。下面開代碼。

package com.szh.login.servlets;

import java.io.IOException;
import java.io.PrintWriter;
import java.util.HashMap;
import java.util.Map;

import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

import net.sf.json.JSONObject;

public class Test extends HttpServlet {

    private static final long serialVersionUID = 1L;

    public void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
        request.setCharacterEncoding("UTF-8");
        response.setCharacterEncoding("UTF-8");
        // response.setContentType("application/json; charset=utf-8");
        // {"result":"0","resultList":[{json},{json},{json}]};
        PrintWriter pw = response.getWriter();
        Map<String, Object> map = new HashMap();
        map.put("result", 0);
        map.put("list", "hello");
        //很簡單直接一句話需要引入jar，這個比較煩有好多。不全的話就會出錯
        JSONObject json = JSONObject.fromObject(map);
        pw.print(json.toString());
        System.out.println("json  :" + json.toString());
        // System.out.println("json object :"+json.toString());

        pw.close();
    }

    public void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {

        this.doGet(request, response);
    }

}

看一下答應結果：

json :{"result":0,"list":"hello"}

所以成功轉換。
需要的jar包連接如下：http://download.csdn.net/detail/qq_35522272/9672266