CodeForces 560B Gerald is into Art【水題】

Description

Gerald bought two very rare paintings at the Sotheby's auction and he now wants to hang them on the wall. For that he bought a special board to attach it to the wall and place the paintings on the board. The board has shape of an a₁ × b₁ rectangle, the paintings have shape of a a₂ × b₂ and a₃ × b₃rectangles.

Since the paintings are painted in the style of abstract art, it does not matter exactly how they will be rotated, but still, one side of both the board, and each of the paintings must be parallel to the floor. The paintings can touch each other and the edges of the board, but can not overlap or go beyond the edge of the board. Gerald asks whether it is possible to place the paintings on the board, or is the board he bought not large enough?

Input

The first line contains two space-separated numbers a₁ and b₁ — the sides of the board. Next two lines contain numbers a₂, b₂, a₃ and b₃ — the sides of the paintings. All numbers a_i, b_i in the input are integers and fit into the range from 1 to 1000.

Output

If the paintings can be placed on the wall, print "YES" (without the quotes), and if they cannot, print "NO" (without the quotes).

Sample Input

Input

3 2
1 3
2 1

Output

YES

Input

5 5
3 3
3 3

Output

NO

Input

4 2
2 3
1 2

Output

YES

Hint

That's how we can place the pictures in the first test:

And that's how we can do it in the third one.

/*
    CodeForces 560B	Gerald is into Art
    題意：有一塊矩形的木板,和兩幅矩形的畫,現在要把畫放在木板上,畫可以旋轉,
          問你能否放進去.
    類型：水題
    分析：枚舉所有可能性暴力試一試就行了
*/
#include<cstdio>
#include<algorithm>
#include<iostream>
using namespace std;
int x,y,a,b,aa,bb;
int ok(){
    if(aa<=x&&bb<=y){
        if(b<=x&&a+bb<=y)return 1;
        if(a<=x&&b+bb<=y)return 1;
        if(b<=y&&a+aa<=x)return 1;
        if(a<=y&&b+aa<=x)return 1;
    }
    if(aa<=y&&bb<=x){
        if(b<=x&&a+bb<=y)return 1;
        if(a<=x&&b+bb<=y)return 1;
        if(b<=y&&a+bb<=x)return 1;
        if(a<=y&&b+bb<=x)return 1;
    }
    return 0;
}
int main()
{
    while(~scanf("%d%d%d%d%d%d",&x,&y,&a,&b,&aa,&bb)){
        int flag=0;
        if(x<y)swap(x,y);
        if(aa<bb)swap(aa,bb);
        if(a<b)swap(a,b);
        if(ok())flag=1;
        if(flag)puts("YES");
        else puts("NO");
    }
    return 0;
}