SQL Server中時間比較

select count(*) from table where DATEDIFF ([second], '2004-09-18 00:00:18', '2004-09-18 00:00:19') > 0

說明

　　[b]select DATEDIFF(day, time1 , time2) [/b] 對應示例語句如下

　　select DATEDIFF(day, '2010-07-23 0:41:18', '2010-07-23 23:41:18')

　　time1 > time2 爲負數;

　　time1 < time2 爲正數;

　　[day] :只會比較 2010-07-23 忽略 0:41:18' 其他同理

以下分別:

　　年: SELECT DATEDIFF([year],time1 , time2)

　　月: SELECT DATEDIFF([month], time1 , time2)

　　天: SELECT DATEDIFF([day], time1 , time2)

　　小時: SELECT DATEDIFF([hour], time1 , time2)

　　秒: SELECT DATEDIFF([second], time1 , time2)