hdu 1228 hdoj 1228

A + B

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 7145    Accepted Submission(s): 4025

Problem Description

讀入兩個小於100的正整數A和B,計算A+B.
需要注意的是:A和B的每一位數字由對應的英文單詞給出.

 

Input

測試輸入包含若干測試用例,每個測試用例佔一行,格式爲"A + B =",相鄰兩字符串有一個空格間隔.當A和B同時爲0時輸入結束,相應的結果不要輸出.

 

Output

對每個測試用例輸出1行,即A+B的值.

 

Sample Input

one + two = three four + five six = zero seven + eight nine = zero + zero =

 

Sample Output

3 90 96

#include<iostream>
#include<cstring>
using namespace std;
string word[]={"zero","one","two","three","four","five","six","seven","eight","nine"};
int main(){
    string cin1,cin2;
    int result=0,A=0,B=0,forward=0,a=0,b=0;
    while(1){
        cin>>cin1>>cin2;
        for(int i=0;i<10;i++){
            if(cin1==word[i]) a=i;
            if(cin2==word[i]) b=i;
        }
        if(cin1!="+"&&cin2!="+"&&cin1!="="&&cin2!="="){
            if(forward==0){
                A=10*(10*A+a)+b;
            }
            else{
                B=10*(10*B+a)+b;
            }
        }
        else if(cin1=="+"){
            result+=A;
            B=10*B+b;
            forward=1;
        }
        else if(cin2=="+"){
            A=10*A+a;
            result+=A;
            forward=1;
        }
        else if(cin1=="="){
            result+=B;
            if(result==0) break;
            cout<<result<<endl;
            result=0,forward=0;
            A=0,B=0;
            A=10*A+b;
        }
        else if(cin2=="="){
            B=10*B+a;
            result+=B;
            if(result==0) break;
            cout<<result<<endl;
            result=0,forward=0,A=0,B=0;
        }
    }
    return 0;
}