Given an integer, convert it to a roman numeral.
Input is guaranteed to be within the range from 1 to 3999.
此題找規律模擬操作,分析1-10的整數是如何構造出羅馬數字的,然後再依葫蘆畫瓢,注意細節的處理。
class Solution {
public:
string IntToR(int k, char mask[])
{
string Res = "";
if(k <= 3)
{
for(int i = 0; i < k; ++i)
{
Res.push_back(mask[0]);
}
}
else if(k == 4)
{
Res.push_back(mask[0]);
Res.push_back(mask[1]);
}
else if(k <= 8)
{
Res.push_back(mask[1]);
for(int i = 0; i < k - 5; ++i)
{
Res.push_back(mask[0]);
}
}
else if(k == 9)
{
Res.push_back(mask[0]);
Res.push_back(mask[2]);
}
return Res;
}
string intToRoman(int num) {
char mask[] = {'I', 'V', 'X', 'L', 'C', 'D', 'M'};
int i = 6;
int factor = 1000;
string Res = "";
while(num != 0)
{
int k = num / factor;
num = num % factor;
factor /= 10;
Res += IntToR(k, &mask[i]);
i -= 2;
}
return Res;
}
};