出處： https://tex.stackexchange.com/questions/33866/algorithm-tag-and-page-break
Latex算法跨頁顯示例子：
\documentclass{article}
\usepackage{algorithm,algpseudocode,float}
\usepackage{lipsum}
\makeatletter
\newenvironment{breakablealgorithm}
{% \begin{breakablealgorithm}
\begin{center}
\refstepcounter{algorithm}% New algorithm
\hrule height.8pt depth0pt \kern2pt% \@fs@pre for \@fs@ruled
\renewcommand{\caption}[2][\relax]{% Make a new \caption
{\raggedright\textbf{\ALG@name~\thealgorithm} ##2\par}%
\ifx\relax##1\relax % #1 is \relax
\addcontentsline{loa}{algorithm}{\protect\numberline{\thealgorithm}##2}%
\else % #1 is not \relax
\addcontentsline{loa}{algorithm}{\protect\numberline{\thealgorithm}##1}%
\fi
\kern2pt\hrule\kern2pt
}
}{% \end{breakablealgorithm}
\kern2pt\hrule\relax% \@fs@post for \@fs@ruled
\end{center}
}
\makeatother
\begin{document}
\listofalgorithms
\section{Some section}
\lipsum[1]
\begin{algorithm}[H]
\caption{Euclid’s algorithm}\label{euclid}
\begin{algorithmic}[1]
\Procedure{Euclid}{$a,b$}\Comment{The g.c.d.\ of~$a$ and~$b$}
\State $r \gets a \bmod b$
\While{$r \neq 0$}\Comment{We have the answer if~$r$ is~$0$}
\State $a \gets b$
\State $b \gets r$
\State $r \gets a \bmod b$
\EndWhile
\State \textbf{return} $b$\Comment{The g.c.d.\ is~$b$}
\EndProcedure
\end{algorithmic}
\end{algorithm}
\lipsum[2]
\begin{breakablealgorithm}
\caption{Euclid’s algorithm}
\begin{algorithmic}[1]
\Procedure{Euclid}{$a,b$}\Comment{The g.c.d.\ of~$a$ and~$b$}
\State $r \gets a \bmod b$
\While{$r \neq 0$}\Comment{We have the answer if~$r$ is~$0$}
\State $a \gets b$
\State $b \gets r$
\State $r \gets a \bmod b$
\EndWhile
\State \textbf{return} $b$\Comment{The g.c.d.\ is~$b$}
\EndProcedure
\end{algorithmic}
\end{breakablealgorithm}
\end{document}