題目1010：A + B

Problem:

Solution:

這道題的關鍵是要搞清楚題目中所蘊含的邏輯關係和運行順序，沒有什麼有含金量的算法，具體詳情看代碼，需要注意的是兩個加數的計算部分，由於輸入即可以形如“six”也可以爲“zero six”也可爲“five six”，因此如何準確的根據輸入情況得到加數就比較關鍵了

#include <iostream>
#include <string>


using namespace std;

string sto[10] = {"zero","one","two","three","four","five","six","seven","eight","nine"};
int converse(string m)
{
    int i;
    for (i = 0;i < 10;i++)
    {
        if(sto[i] == m) return i;
    }
    return -1;
}

int main()
{
    string m;
    bool flag = true;
    int first = 0,second = 0;
    while (cin >> m)
    {
        int t = converse(m);
        if (t != -1 && flag)
        {
            first *= 10;
            first += t;
        }
        else if(t != -1 && !flag)
        {
            second *= 10;
            second += t;
        }
        else if (t == -1 && m == "+")
        {
            flag = false;
        }
        else if (t == -1 && m == "=")
        {
            if (first == 0 && second == 0) break;
            cout << first+second << endl;
            flag = true;
            first = 0;
            second = 0;
        }
    }
    return 0;
}