Map String數組的使用(業務邏輯)---實際項目中的問題

有一堆數據:String bom = "AAAA=1,BBBBB=2,CCCC=3,AAAA=1,BBBBB=2,CCCC=312134";

需要取得的結果爲去重複的key,把Value值相加:{AAAA=3, BBBBB=6, CCCC=312140}

第一種方法:(老大寫的) 效率高.簡單.等.

package wsc.com.it.repeatString;

import java.util.LinkedHashMap;
import java.util.Map;


public class BomString {


public static void main(String[] args) {
String bom = "AAAA=1,BBBBB=2,CCCC=3,AAAA=1,BBBBB=2,CCCC=312134";
bom = processBom(bom);
System.out.println(bom);
}


private static String processBom(String bom) {
if (bom == null) {
return null;
}
String bomData = null;
String[] srcBom = bom.trim().split(",");

Map<String , Long> bomMap = new  LinkedHashMap<String, Long>(0);

//去掉重複的Key  取得Value值

for (int i = 0; i < srcBom.length; i++) {

String bom1 = srcBom[i];
String[] bomTemp = bom1.split("=");
String key = bomTemp[0].trim();
Long totle = Long.parseLong(bomTemp[1].trim().toString());
if (bomMap.get(key)==null) {
bomMap.put(key, totle);
}
bomMap.put(key, Long.parseLong(bomMap.get(key).toString())+totle);
}
bomData = bomMap.toString().replace("\\{","").replace("\\}", "");
return bomData;
}

}

第二種方法(自己寫的);效率低.循環多.代碼複雜  .但功能是實現了的..呵呵..待發.....