《C語言及程序設計初步》第26講實踐項目

項目4 這個月有多少天？

流程圖：

程序：

//這個月多少天？
#include <stdio.h>
int main()
{
    int year,month;
    printf("Please enter the year and month:");
    scanf("%d %d",&year,&month);
    switch(month)
    {
        case 1:
        case 3:
        case 5:
        case 7:
        case 8:
        case 10:
        case 12:
            printf("The month has 31 days.");
            break;
        case 4:
        case 6:
        case 9:
        case 11:
            printf("The month has 30 days.");
            break;
        case 2:
            if((year%4==0 && year%100!=0) || year%400==0)
            {
                printf("The month has 29 days.\n");
            }
            else
            {
                printf("The month has 28 days.\n");
            }
    }
    return 0;
}

項目5：

流程圖：

程序：

//計算個人所得稅 individual income tax
#include <stdio.h>
int main()
{
    double dSalary,dTax,c;
    int t;
    printf("Please enter the salary:");
    scanf("%lf",&dSalary);

    if(dSalary<=3500)
    {
        dTax = 0;
        printf("Tax=%.2lf Netincome=%.2lf\n",dTax,(dSalary-dTax));
    }
    else
    {
        c = dSalary-3500;
        if(c>80000)
        {
            dTax = c*0.45-13505;
            printf("Tax=%.2lf Netincome=%.2lf\n",dTax,(dSalary-dTax));
        }
        else
        {
            t = (c<=1500)+(c<=4500)+(c<=9000)+(c<=35000)+(c<=55000)+(c<=80000);
            switch(t)
            {
                case 6:
                    dTax = c*0.03;break;
                case 5:
                    dTax = c*0.1-105;break;
                case 4:
                    dTax = c*0.2-555;break;
                case 3:
                    dTax = c*0.25-1005;break;
                case 2:
                    dTax = c*0.3-2755;break;
                case 1:
                    dTax = c*0.35-5505;break;
            }
            printf("Tax=%.2lf Netincome=%.2lf\n",dTax,(dSalary-dTax));
        }
    }
    return 0;
}

項目6：

//計算利息和本息和
#include <stdio.h>
int main()
{
    float rate,interest,money,time;
    int type;
    printf("歡迎使用利息計算器!\n");
    printf("請輸入存款金額:");
    scanf("%f",&money);
    printf("======存款期限======\n");
    printf("1. 3個月\n");
    printf("2. 6個月\n");
    printf("3. 一年 \n");
    printf("4. 二年 \n");
    printf("5. 三年 \n");
    printf("6. 五年 \n");
    printf("請輸入存款期限的代號:");
    scanf("%d",&type);
    if(type>=1 && type<=6)
    {
        switch(type)
        {
            case 1:
                time=0.25;rate=0.031;break;
            case 2:
                time=0.5;rate=0.033;break;
            case 3:
                time=1;rate=0.035;break;
            case 4:
                time=2;rate=0.044;break;
            case 5:
                time=3;rate=0.05;break;
            case 6:
                time=5;rate=0.055;break;
        }
        interest = money*rate*time;
        printf("到期利息爲:%f\n",interest);
        printf("本息合計共:%f\n",interest+money);
    }
    else
    {
        printf("選擇存款類型錯誤!\n");
    }
    printf("感謝您的使用，歡迎下次光臨!");
    return 0;
}

項目7：

//製作簡易菜單
#include <stdio.h>
int main()
{
    int t;
    printf("====今天晚飯吃什麼?====\n");
    printf("1. 山西刀削麪\n");
    printf("2. 蘭州拉麪\n");
    printf("3. 西安羊肉泡饃\n");
    printf("4. 煙臺燜子\n");
    printf("5. 西北風\n");
    printf("請輸入您選擇的代號:");
    scanf("%d",&t);
    switch(t)
    {
        case 1:
            printf("山西刀削麪，要得!");break;
        case 2:
            printf("蘭州拉麪，湯好面好!");break;
        case 3:
            printf("西安羊肉泡饃，眼淚嘩嘩的!");break;
        case 4:
            printf("煙臺燜子，啥也不說了!");break;
        case 5:
            printf("西北風，咋?還有這道菜?");break;
        default:
            printf("這回真喝西北風了!");
    }
    return 0;
}