二分
難度:簡單
推薦學習視頻:花花醬
class Solution {
public:
char nextGreatestLetter(vector<char>& letters, char target) {
//2020.2.27 二分 左閉有開
int n = letters.size();
int l = 0, r = n;
while(l < r){
int mid = l + r >> 1;
if(letters[mid] <= target) l = mid + 1;
else r = mid;
}
return letters[l%n];
}
};