Java併發編程 - 線程不安全類與解決方案(List)

List

package com.mmall.concurrency.example.commonUnsafe;

import com.mmall.concurrency.annoations.NotThreadSafe;
import lombok.extern.slf4j.Slf4j;
import java.util.ArrayList;
import java.util.List;
import java.util.concurrent.CountDownLatch;
import java.util.concurrent.ExecutorService;
import java.util.concurrent.Executors;
import java.util.concurrent.Semaphore;

@Slf4j
@NotThreadSafe
public class ArrayListExample {

    // 請求總數
    public static int clientTotal = 5000;

    // 同時併發執行的線程數
    public static int threadTotal = 200;

    private static List<Integer> list = new ArrayList<>();

    public static void main(String[] args) throws Exception {
        ExecutorService executorService = Executors.newCachedThreadPool();
        final Semaphore semaphore = new Semaphore(threadTotal);
        final CountDownLatch countDownLatch = new CountDownLatch(clientTotal);
        for (int i = 0; i < clientTotal; i++) {
            final int count = i;
            executorService.execute(() -> {
                try {
                    semaphore.acquire();
                    update(count);
                    semaphore.release();
                } catch (Exception e) {
                    log.error("exception", e);
                }
                countDownLatch.countDown();
            });
        }
        countDownLatch.await();
        executorService.shutdown();
        log.info("size:{}", list.size());
    }

    private static void update(int i) {
        list.add(i);
    }
}

// 輸出
size:4988

 

解決方案一(Vector)

package com.mmall.concurrency.example.syncContainer;

import com.mmall.concurrency.annoations.ThreadSafe;
import lombok.extern.slf4j.Slf4j;
import java.util.List;
import java.util.Vector;
import java.util.concurrent.CountDownLatch;
import java.util.concurrent.ExecutorService;
import java.util.concurrent.Executors;
import java.util.concurrent.Semaphore;

@Slf4j
@ThreadSafe
public class VectorExample1 {

    // 請求總數
    public static int clientTotal = 5000;

    // 同時併發執行的線程數
    public static int threadTotal = 200;

    private static List<Integer> list = new Vector<>();

    public static void main(String[] args) throws Exception {
        ExecutorService executorService = Executors.newCachedThreadPool();
        final Semaphore semaphore = new Semaphore(threadTotal);
        final CountDownLatch countDownLatch = new CountDownLatch(clientTotal);
        for (int i = 0; i < clientTotal; i++) {
            final int count = i;
            executorService.execute(() -> {
                try {
                    semaphore.acquire();
                    update(count);
                    semaphore.release();
                } catch (Exception e) {
                    log.error("exception", e);
                }
                countDownLatch.countDown();
            });
        }
        countDownLatch.await();
        executorService.shutdown();
        log.info("size:{}", list.size());
    }

    private static void update(int i) {
        list.add(i);
    }
}

// 輸出
size:5000

 

解決方案二(同步容器:synchronizedList)

package com.mmall.concurrency.example.syncContainer;

import com.google.common.collect.Lists;
import com.mmall.concurrency.annoations.ThreadSafe;
import lombok.extern.slf4j.Slf4j;
import java.util.Collections;
import java.util.List;
import java.util.Vector;
import java.util.concurrent.CountDownLatch;
import java.util.concurrent.ExecutorService;
import java.util.concurrent.Executors;
import java.util.concurrent.Semaphore;

@Slf4j
@ThreadSafe
public class CollectionsExample1 {

    // 請求總數
    public static int clientTotal = 5000;

    // 同時併發執行的線程數
    public static int threadTotal = 200;

    private static List<Integer> list = Collections.synchronizedList(Lists.newArrayList());

    public static void main(String[] args) throws Exception {
        ExecutorService executorService = Executors.newCachedThreadPool();
        final Semaphore semaphore = new Semaphore(threadTotal);
        final CountDownLatch countDownLatch = new CountDownLatch(clientTotal);
        for (int i = 0; i < clientTotal; i++) {
            final int count = i;
            executorService.execute(() -> {
                try {
                    semaphore.acquire();
                    update(count);
                    semaphore.release();
                } catch (Exception e) {
                    log.error("exception", e);
                }
                countDownLatch.countDown();
            });
        }
        countDownLatch.await();
        executorService.shutdown();
        log.info("size:{}", list.size());
    }

    private static void update(int i) {
        list.add(i);
    }
}

// 輸出
szie:5000

 

解決方案三(併發容器:CopyOnWriteArrayList)

package com.mmall.concurrency.example.concurrent;

import com.mmall.concurrency.annoations.ThreadSafe;
import lombok.extern.slf4j.Slf4j;
import java.util.ArrayList;
import java.util.List;
import java.util.concurrent.CopyOnWriteArrayList;
import java.util.concurrent.CountDownLatch;
import java.util.concurrent.ExecutorService;
import java.util.concurrent.Executors;
import java.util.concurrent.Semaphore;

@Slf4j
@ThreadSafe
public class CopyOnWriteArrayListExample {

    // 請求總數
    public static int clientTotal = 5000;

    // 同時併發執行的線程數
    public static int threadTotal = 200;

    private static List<Integer> list = new CopyOnWriteArrayList<>();

    public static void main(String[] args) throws Exception {
        ExecutorService executorService = Executors.newCachedThreadPool();
        final Semaphore semaphore = new Semaphore(threadTotal);
        final CountDownLatch countDownLatch = new CountDownLatch(clientTotal);
        for (int i = 0; i < clientTotal; i++) {
            final int count = i;
            executorService.execute(() -> {
                try {
                    semaphore.acquire();
                    update(count);
                    semaphore.release();
                } catch (Exception e) {
                    log.error("exception", e);
                }
                countDownLatch.countDown();
            });
        }
        countDownLatch.await();
        executorService.shutdown();
        log.info("size:{}", list.size());
    }

    private static void update(int i) {
        list.add(i);
    }
}

// 輸出
size:5000

分析

  • CopyOnWriteArrayList 寫操作時複製,當有新元素添加到集合中時,從原有的數組中拷貝一份出來,然後在新的數組上作寫操作,然後將原來的數組指向新的數組。整個數組的add操作都是在鎖的保護下進行的,防止併發時複製多份副本。讀操作是在原數組中進行,不需要加鎖。

缺點

  1. 寫操作時複製消耗內存
  2. 不能用於實時讀的場景
  3. 由於複製和add操作等需要時間,故讀取時可能讀到舊值。
  4. 能做到最終一致性,但無法滿足實時性的要求,更適合讀多寫少的場景。
  5. 如果無法知道數組有多大,或者add、set操作有多少,慎用此類。

設計思想

  1. 讀寫分離
  2. 最終一致性
  3. 使用時另外開闢空間,防止併發衝突

 

附1:Vector 線程不安全情景

package com.mmall.concurrency.example.syncContainer;

import com.mmall.concurrency.annoations.NotThreadSafe;
import java.util.Vector;

@NotThreadSafe
public class VectorExample2 {

    private static Vector<Integer> vector = new Vector<>();

    public static void main(String[] args) {

        while (true) {

            for (int i = 0; i < 10; i++) {
                vector.add(i);
            }

            Thread thread1 = new Thread() {
                public void run() {
                    for (int i = 0; i < vector.size(); i++) {
                        vector.remove(i);
                    }
                }
            };

            Thread thread2 = new Thread() {
                public void run() {
                    for (int i = 0; i < vector.size(); i++) {
                        vector.get(i);
                    }
                }
            };
            thread1.start();
            thread2.start();
        }
    }
}

5e9560e30001869c19201080.jpg (1920×1080)

  • 輸出結果報錯,因爲 remove 和 get 分別是不同對象調用的不同 sync 方法,很有可能出現 remove 在 get 之前操作。

 

附2:Vector for & foerach & iterator

package com.mmall.concurrency.example.syncContainer;

import java.util.Iterator;
import java.util.Vector;

public class VectorExample3 {

    // java.util.ConcurrentModificationException
    private static void test1(Vector<Integer> v1) { // foreach
        for(Integer i : v1) {
            if (i.equals(3)) {
                v1.remove(i);
            }
        }
    }

    // java.util.ConcurrentModificationException
    private static void test2(Vector<Integer> v1) { // iterator
        Iterator<Integer> iterator = v1.iterator();
        while (iterator.hasNext()) {
            Integer i = iterator.next();
            if (i.equals(3)) {
                v1.remove(i);
            }
        }
    }

    // success
    private static void test3(Vector<Integer> v1) { // for
        for (int i = 0; i < v1.size(); i++) {
            if (v1.get(i).equals(3)) {
                v1.remove(i);
            }
        }
    }

    public static void main(String[] args) {

        Vector<Integer> vector = new Vector<>();
        vector.add(1);
        vector.add(2);
        vector.add(3);
        test1(vector);
    }
}

5e9563c90001b6d019201080.jpg (1920×1080)

  • 輸出結果

5e9563dd00018d1119201080.jpg (1920×1080)

  • 源碼分析,因爲 modCount 只要更新操作會被修改導致這裏不相等拋出異常。

結論

使用foreach,iterator以及for循環對集合類遍歷的同時進行修改

  1. 在foreach、iterator迭代器循環集合的時候,在遍歷過程中儘量不要做更新操作。
  2. 如果一定要做的話,在遍歷過程中,只做標記,遍歷完成後再更新。
  3. 遍歷過程中(foeach,iterator)更新會導致ConcurrentModificationException
  4. 可以用for循環做遍歷過程中的增刪操作
發表評論
所有評論
還沒有人評論,想成為第一個評論的人麼? 請在上方評論欄輸入並且點擊發布.
相關文章