1.鬥地主的需求分析:
2.鬥地主的代碼實現:
//鬥地主準備案例
//1.準備牌 2.洗牌 3.發牌 4.看牌
public class Doudizhu {
public static void main(String[] args) {
//1.準備牌
//定義一個存儲54張牌的ArrayList集合,泛型使用String
ArrayList<String> poker = new ArrayList<>();
//定義兩個數組,一個數組存儲牌的花色,一個數組存儲牌的序號
String [] colors = {"♠","♣","♣","♦"};
String [] numbers={"2","A","K","Q","J","10","9","8","7","6","5","4","3"};
//先把大王和小王存儲到poker
poker.add("大王");
poker.add("小王");
//循環嵌套遍歷兩個數組,組裝52張牌
for(String number : numbers){
for (String color : colors) {
//System.out.println(color+number);
//把組裝好的牌存儲到poker集合中
poker.add(color+number);
}
}
//System.out.println(poker);
//2.洗牌
//使用集合的工具類Collections中的方法
//static void shuffle<List<?> list >
Collections.shuffle(poker);
// System.out.println(poker);
//3.發牌
//定義4個集合,存儲玩家的牌和底牌
ArrayList<String>player01 = new ArrayList<>();
ArrayList<String>player02 = new ArrayList<>();
ArrayList<String>player03 = new ArrayList<>();
ArrayList<String> dipai = new ArrayList<>();
/*
遍歷poker集合,獲取每一張牌
使用poker集合的索引%3給3個玩家輪流發牌
剩餘3張牌給底牌
注意:先判斷底牌(i>=51),否則牌就發沒了
*/
for (int i = 0; i<poker.size();i++){
//獲取每一張牌
String p =poker.get(i);
//輪流發牌
if (i>=51){
//給底牌發牌
dipai.add(p);
}else if(i%3==0){
//給玩家1發牌
player01.add(p);
}else if(i%3==1){
//給玩家2發牌
player02.add(p);
}else if(i%3==2){
//給玩家3發牌
player03.add(p);
}
}
//4.看牌
System.out.println("劉德華"+player01);
System.out.println("周星馳"+player02);
System.out.println("周潤發"+player03);
System.out.println("底牌"+dipai);
}
}