1.斗地主的需求分析:
2.斗地主的代码实现:
//斗地主准备案例
//1.准备牌 2.洗牌 3.发牌 4.看牌
public class Doudizhu {
public static void main(String[] args) {
//1.准备牌
//定义一个存储54张牌的ArrayList集合,泛型使用String
ArrayList<String> poker = new ArrayList<>();
//定义两个数组,一个数组存储牌的花色,一个数组存储牌的序号
String [] colors = {"♠","♣","♣","♦"};
String [] numbers={"2","A","K","Q","J","10","9","8","7","6","5","4","3"};
//先把大王和小王存储到poker
poker.add("大王");
poker.add("小王");
//循环嵌套遍历两个数组,组装52张牌
for(String number : numbers){
for (String color : colors) {
//System.out.println(color+number);
//把组装好的牌存储到poker集合中
poker.add(color+number);
}
}
//System.out.println(poker);
//2.洗牌
//使用集合的工具类Collections中的方法
//static void shuffle<List<?> list >
Collections.shuffle(poker);
// System.out.println(poker);
//3.发牌
//定义4个集合,存储玩家的牌和底牌
ArrayList<String>player01 = new ArrayList<>();
ArrayList<String>player02 = new ArrayList<>();
ArrayList<String>player03 = new ArrayList<>();
ArrayList<String> dipai = new ArrayList<>();
/*
遍历poker集合,获取每一张牌
使用poker集合的索引%3给3个玩家轮流发牌
剩余3张牌给底牌
注意:先判断底牌(i>=51),否则牌就发没了
*/
for (int i = 0; i<poker.size();i++){
//获取每一张牌
String p =poker.get(i);
//轮流发牌
if (i>=51){
//给底牌发牌
dipai.add(p);
}else if(i%3==0){
//给玩家1发牌
player01.add(p);
}else if(i%3==1){
//给玩家2发牌
player02.add(p);
}else if(i%3==2){
//给玩家3发牌
player03.add(p);
}
}
//4.看牌
System.out.println("刘德华"+player01);
System.out.println("周星驰"+player02);
System.out.println("周润发"+player03);
System.out.println("底牌"+dipai);
}
}