短路運算---賦值語句【printf("%d\n", (x = 0) && (y = 3)); printf("x=%d y=%d\n ", x, y);】

#include <stdio.h>

int main()
{
    int a = -1;
    printf("(a = -1): %d\n", (a = -1));

    printf("\n------\n\n");

    int a1 = 0;
    printf("(a1 =0): %d\n", (a1 = 0));

    printf("\n------\n\n");

    int x = 2, y = 2;
    printf("(x=2): %d\n", (x = 2));
    printf("%d\n", (x = 0) && (y = 3)); //0
    printf("(x=0): %d\n", (x = 0));
    printf("x=%d    y=%d\n ", x, y); //x=0    y=2

    printf("\n------\n\n");

    int x1 = 2, y1 = 2;
    printf("%d  \n", (x1 = 4) || (y1 = 4)); //1
    printf("(x=1): %d\n", (x = 1));
    printf("x=%d    y=%d\n ", x1, y1); //x=4    y=2

    return 0;
}