*LeetCode Mysql查找排名前n的數值

編寫一個 SQL 查詢，找出每個部門獲得前三高工資的所有員工

Employee:

Id	Name	Salary	DepartmentId
1	Joe	85000	1
2	Henry	80000	2
3	Sam	60000	2
4	Max	90000	1
5	Janet	69000	1
6	Randy	85000	1
7	Will	70000	1

Department:

Id	Name
1	IT
2	Sales

All in the Code:

SELECT 
    d.Name AS "Department", e1.Name AS "Employee", e1.Salary
FROM
    Employee e1 JOIN Department d 
    on e1.DepartmentId = d.Id
WHERE
    3 > (SELECT COUNT(DISTINCT e2.Salary)
        FROM 
            Employee e2
        WHERE
            e2.Salary > e1.Salary
            AND e1.DepartmentId = e2.DepartmentId);

Return:

Department	Employee	Salary
IT	Max	90000
IT	Randy	85000
IT	Joe	85000
IT	Will	70000
Sales	Henry	80000
Sales	Sam	60000