(1)方法一:
select stuff((select '|'+words from dbo.FilterWords for xml path('')),1,1,'')
(2)方法二:
declare @string varchar(2000)
set @string=''
select @string+=cast(words as varchar)+'|' from dbo.FilterWords
select @string
結果:
已 “ | ”分隔的一個字段
(1)方法一:
select stuff((select '|'+words from dbo.FilterWords for xml path('')),1,1,'')
(2)方法二:
declare @string varchar(2000)
set @string=''
select @string+=cast(words as varchar)+'|' from dbo.FilterWords
select @string
結果:
已 “ | ”分隔的一個字段