/*。
*Copyright(c)2014,煙臺大學計算機學院
*All right reserved,
*文件名:test.cpp
*作者:畢玉堂
*完成日期:2015年5月17日
*版本號:v1.0
*
問題描述:
*輸入描述:
*程序輸出:
*/
#include <iostream>
#include<Cmath>
#include<cstdlib>
using namespace std;
int gcd(int m, int n);
class CFraction
{
private:
int nume; // 分子
int deno; // 分母
public:
friend istream& operator>>(istream &,CFraction &);
friend ostream& operator<<(ostream &,const CFraction &);
CFraction(int nu=0,int de=1):nume(nu),deno(de){} //構造函數,初始化用
void set(int nu=0,int de=1);//置值,改變值時用
CFraction operator+(const CFraction &c);
CFraction operator-(const CFraction &c);
CFraction operator*(const CFraction &c);
CFraction operator/(const CFraction &c);
bool operator>(const CFraction &c);
bool operator<(const CFraction &c);
bool operator==(const CFraction &c);
bool operator!=(const CFraction &c);
bool operator>=(const CFraction &c);
bool operator<=(const CFraction &c);
void input(); //按照"nu/de"的格式,如"5/2"的形式輸入
void simplify(); //化簡(使分子分母沒有公因子)
void amplify(int n); //放大n倍,如2/3放大5倍爲10/3
void output(int style);
//輸出:以8/6爲例,style爲0時,原樣輸出8/6;
//style爲1時,輸出化簡後形式4/3;
//style爲2時,輸出1(1/3)形式,表示一又三分之一;
//style爲3時,用小數形式輸出,如1.3333;
//默認方式0
CFraction operator+();//取正
CFraction operator-();//求反
CFraction operator~();//求倒數
};
void CFraction::set(int nu,int de)
{
if(de!=0)
{
nume=nu;
deno=de;
}
}
CFraction CFraction::operator+(const CFraction &c)
{
CFraction a;
a.nume=nume*c.deno+c.nume*deno;
a.deno=deno*c.deno;
a.simplify();
return a;
}
CFraction CFraction::operator-(const CFraction &c)
{
CFraction a;
a.nume=nume*c.deno-c.nume*deno;
a.deno=deno*c.deno;
a.simplify();
return a;
}
CFraction CFraction::operator*(const CFraction &c)
{
CFraction a;
a.nume=nume*c.nume;
a.deno=deno*c.deno;
a.simplify();
return a;
}
CFraction CFraction::operator/(const CFraction &c)
{
CFraction a;
a.nume=nume*c.deno;
a.deno=deno*c.nume;
a.simplify();
return a;
}
bool CFraction::operator>(const CFraction &c)
{
if((nume*c.deno>c.nume*deno&&deno*c.deno>0)||(nume*c.deno<c.nume*deno&&deno*c.deno<0))
return true;
return false;
}
bool CFraction::operator<(const CFraction &c)
{
if((nume*c.deno<c.nume*deno&&deno*c.deno>0)||(nume*c.deno>c.nume*deno&&deno*c.deno<0))
return true;
return false;
}
bool CFraction::operator==(const CFraction &c)
{
if(*this!=c)
return false;
return true;
}
bool CFraction::operator!=(const CFraction &c)
{
if(*this>c||*this<c)
return true;
return false;
}
bool CFraction::operator>=(const CFraction &c)
{
if(*this<c)
return false;
return true;
}
bool CFraction::operator<=(const CFraction &c)
{
if(*this>c)
return false;
return true;
}
istream &operator>>(istream &in,CFraction &x)
{
char ch;
while(1)
{
cin>>x.nume>>ch>>x.deno;
if (x.deno==0)
cerr<<"分母爲0, 請重新輸入\n";
else if(ch!='/')
cerr<<"格式錯誤(形如m/n)! 請重新輸入\n";
else
break;
}
return cin;
}
ostream& operator<<(ostream &out,const CFraction &x)
{
out<<x.nume<<"/"<<x.deno<<endl;
return out;
}
void CFraction::simplify()
{
int n=gcd(deno, nume);
deno/=n; // 化簡
nume/=n;
}
// 求m,n的最大公約數
int gcd(int m, int n) //這個函數可以定義爲類的成員函數,也可以爲一般函數
{
int r;
while(n!=0)
{
r=m%n;
m=n;
n=r;
}
return m;
}
void CFraction::amplify(int n)
{
nume*=n;
}
CFraction CFraction::operator+()
{
CFraction c;
if(nume<0&&deno>0)
{
c.nume=-nume;
c.deno=deno;
}
else if(nume>0&&deno<0)
{
c.nume=nume;
c.deno=-deno;
}
else
{
c.nume=nume;
c.deno=deno;
}
return c;
}
CFraction CFraction::operator-()
{
CFraction c;
c.nume=-nume;
c.deno=deno;
return c;
}
CFraction CFraction::operator~()
{
CFraction c;
c.nume=deno;
c.deno=nume;
return c;
}
int main()
{
CFraction x,y,s;
cin>>x>>y;
s=x+y;
cout<<"x+y=";
cout<<s;
s=x-y;
cout<<"x-y=";
cout<<s;
s=x*y;
cout<<"x*y=";
cout<<s;
s=x/y;
cout<<"x/y=";
cout<<s;
cout<<x;
if (x>y) cout<<"大於"<<endl;
if (x<y) cout<<"小於"<<endl;
if (x==y) cout<<"等於"<<endl;
cout<<y;
cout<<endl;
s=+y;
cout<<"y取正爲:";
cout<<s;
s=-y;
cout<<"y的相反數爲:";
cout<<s;
s=~x;
cout<<"x的倒數爲:";
cout<<s;
return 0;
}
運行結果: