Evaluate the value of an arithmetic expression in Reverse Polish Notation.
Valid operators are +, -, *, /. Each operand may be an integer or another expression.
Some examples:
[“2”, “1”, “+”, “3”, ““] -> ((2 + 1) 3) -> 9
[“4”, “13”, “5”, “/”, “+”] -> (4 + (13 / 5)) -> 6
解題思路:棧的應用
從前往後遍歷數組,遇到數字則壓入棧中,遇到符號,則把棧頂的兩個數字拿出來運算,把結果再壓入棧中,直到遍歷完整個數組,棧頂數字即爲最終答案
import java.util.Scanner;
import java.util.Stack;
public class l150_reverse_polish_notation {
public int evalRPN(String[] tokens) {
Stack<Integer> s=new Stack<>();
for(int i=0;i<tokens.length;i++){
if(tokens[i].equals("+")||tokens[i].equals("-")||tokens[i].equals("*")||tokens[i].equals("/")){
int num2=s.pop();
int num1=s.pop();
s.push(operate(tokens[i],num1,num2));
}
else{
s.push(Integer.valueOf(tokens[i]));
}
}
return s.pop();
}
public int operate(String op,int num1,int num2){
if(op.equals("+"))
return num1+num2;
if(op.equals("-"))
return num1-num2;
if(op.equals("*"))
return num1*num2;
if(op.equals("/"))
return num1/num2;
return 0;
}
public static void main(String[] args) {
l150_reverse_polish_notation c=new l150_reverse_polish_notation();
Scanner scanner=new Scanner(System.in);
String[] tokens=new String[5];
for(int i=0;i<tokens.length;i++){
tokens[i]=scanner.next();
}
int res=c.evalRPN(tokens);
System.out.println(res);
}
}
貼一下牛客上的答案,異常處理應用:
鏈接:https://www.nowcoder.com/questionTerminal/22f9d7dd89374b6c8289e44237c70447
來源:牛客網
import java.util.Stack;
public class Solution {
public int evalRPN(String[] tokens) {
Stack<Integer> stack = new Stack<Integer>();
for(int i = 0;i<tokens.length;i++){
try{
int num = Integer.parseInt(tokens[i]);
stack.add(num);
}catch (Exception e) {
int b = stack.pop();
int a = stack.pop();
stack.add(get(a, b, tokens[i]));
}
}
return stack.pop();
}
private int get(int a,int b,String operator){
switch (operator) {
case "+":
return a+b;
case "-":
return a-b;
case "*":
return a*b;
case "/":
return a/b;
default:
return 0;
}
}
}