Alice and Bob like game. They often play the game together.
Today, they are playing a card game. At first, there are
NN
cards on table. Each cards have a number. The rules of this game is follow:
First, Alice choose one card from the first card and the last card.
And then Bob choose one card from the first card and the last card of the remaningN−1N−1
cards.
And then Alice choose one card from the first card and the last card of the remaningN−2N−2
cards.
...end until there is no card.
they can get points from the number on the cards. The winner whose point is most.
For example, there are 3 cards, 3 7 5. First, Alice can choose 3 and 5. Alice choose 5, and then Bob can choose 3 and 7, Bob choose 7, and then Alice choose 3. The point of Alice is 8, and point of Bob is 7. So Alice is winner, and the difference of points
is 1.
Now, give you NN
cards. We can assume that Alice and Bob are very smart, you need tell us the difference of the point of Alice and Bob.
Input
The input consists of multiple test cases. The first line contains an integer
TT,
indicating the number of test cases.(1≤T≤10)(1≤T≤10)
Each case contains two lines, the first line contains one integer
NN,
means the number of cards.(1≤N≤20)(1≤N≤20)
The second contains NN
positive numbers means the point on the card. the point on the card is less than104104
Output
For each case output the difference of points of Alice and Bob
Sample Input
3 3 3 10 5 4 3 7 8 5 4 1 1 1 1
Sample Output
-2 1 0
#include <iostream>
#include <string>
#include<cstdlib>
using namespace std;
int main()
{
int t,n,i;
int a[20];
cin>>t;//用例組數
int beg,fin;
int alice,bob;
while(t--)
{
alice=0;
bob=0;
cin>>n;
beg=0;
fin=n-1;
for(i=0;i<n;i++)
cin>>a[i];
for(i=1;i<=n;i++)
{
if(beg<=fin)
{
if(i%2!=0)//alice選擇
{
if(a[beg]>=a[fin])
{
alice+=a[beg];
beg++;
}
else if(a[beg]<=a[fin])
{
alice+=a[fin];
fin--;
}
}
else//bob選
{
if(a[beg]>=a[fin])
{
bob+=a[beg];
beg++;
}
else if(a[beg]<=a[fin])
{
bob+=a[fin];
fin--;
}
}
}
}
cout<<alice-bob<<endl;
}
return 0;
}