You are climbing a stair case. It takes n steps to reach to the top.
Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top?
Note: Given n will be a positive integer.
Example 1:
Input: 2 Output: 2 Explanation: There are two ways to climb to the top. 1. 1 step + 1 step 2. 2 steps
Example 2:
Input: 3 Output: 3 Explanation: There are three ways to climb to the top. 1. 1 step + 1 step + 1 step 2. 1 step + 2 steps 3. 2 steps + 1 step
//斐波那契數列f(n) = f(n-1) + f(n -2)
public static int climbStairs(int n) {
if(n ==1){
return 1;
}
if(n ==2){
return 2;
}
int f1 = 1;
int f2 = 2;
for (int i = 3; i <=n; i++) {
int f3 = f1 + f2;
f1 = f2;
f2 = f3;
}
return f2;
// return climbStairs(n-1) + climbStairs(n-2);
}