python使用正則表達式解析http url

http Get的原文
/alter?user=abcde&pwd=123456

re.compile(r'/(?P<url_path>alter)\?(?P<query>user=(?P<user>[a-zA-Z]{5,10})&pwd=(?P<passwd>(?:\d|\w){6,}?))$')

• step1

(?P<url_path>alter)

找到匹配的http path( alter ),同時命名爲url_path

• step2

(?P<query>user=(?P<user>[a-zA-Z]{5,10})&pwd=(?P<passwd>(?:\d|\w){6,}?))

匹配query-string .並命名爲query

• step3

user=(?P<user>[a-zA-Z]{5,10})

匹配user

• step4

pwd=(?P<passwd>(?:\d|\w){6,}?)

匹配pwd,其中?爲非貪婪模式.

運行結果:

>>> p=re.compile(r'/(?P<url_path>alter)\?(?P<query>user=(?P<user>[a-zA-Z]{5,10})&pwd=(?P<passwd>(?:\d|\w){6,}?))$')
>>> p.match('/alter?user=liujxc&pwd=123456').groups()
('alter', 'user=liujxc&pwd=123456', 'liujxc', '123456')