解析:A+Bi=RcosP+R*isinP
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a+bi 和 c+di
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加法:(a+c) + (b+d)i
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減法:(a-c) + (b-d)i
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乘法:(ac-bd) + (bc+ad)i
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除法:(ac+bd)/(cc+dd) + (bc+ad)/(cc+dd)i
這題我就懵了,複數已經忘光了,沒想到居然會考到,在這裏複習一下,還需要注意的一個點就是輸出之前要判斷一下,a和b是否小於0.01如果小於直接將a和b的值改變爲0;
public class Pta_1051 {
public static void main(String[] args) throws IOException {
BufferedReader buf = new BufferedReader(new InputStreamReader(System.in));
String[] split = buf.readLine().split("\\s");
double R1= Double.parseDouble(split[0]);
double P1= Double.parseDouble(split[1]);
double R2= Double.parseDouble(split[2]);
double P2= Double.parseDouble(split[3]);
double A1=R1*(Math.cos(P1));
double A2=R2*(Math.cos(P2));
double B1=R1*(Math.sin(P1));
double B2=R2*(Math.sin(P2));
double A=A1*A2-B1*B2;
double B=A2*B1+B2*A1;
if (Math.abs(A) < 0.01) {
A = 0;
}
if (Math.abs(B) < 0.01) {
B = 0;
}
System.out.println(A);
System.out.println(B);
System.out.printf("%.2f%+.2fi\n", A, B);
}
}