form提交 jquery ajax

<script language="javascript" type="text/javascript" src="/js/jquery/jquery-1.4.2.min.js"></script>
<script language="javascript" type="text/javascript" src="/js/jquery/jquery.form.js"></script>

function submitForm(){

$.ajax({
   type: "POST",
   url:"/serviceMoney/serviceMoney.do?method=modiOK",
   data:$("#theform").serialize(),// 你的formid
   success: function(data) {
       alert("修改成功");
   }
});

}

<form action="/serviceMoney/serviceMoney.do?method=modiOK" method="post" id="theform">
<input name="serviceMoney_id" type="hidden"  value="${item.serviceMoney_id}"/>
  <input type="button" value="修改" οnclick="submitForm()"/>
</form>