Python3 實現爬取網站下所有URL方式

今天小編就爲大家分享一篇Python3 實現爬取網站下所有URL方式,具有很好的參考價值,希望對大家有所幫助。一起跟隨小編過來看看吧
獲取首頁元素信息:

目標 test_URL:http://www.xxx.com.cn/

首先檢查元素,a 標籤下是我們需要爬取得鏈接,通過獲取鏈接路徑,定位出我們需要的信息

soup = Bs4(reaponse.text, "lxml")
urls_li = soup.select("#mainmenu_top > div > div > ul > li")

首頁的URL鏈接獲取:

完成首頁的URL鏈接獲取,具體代碼如下:

'''
遇到不懂的問題?Python學習交流羣:821460695滿足你的需求,資料都已經上傳羣文件,可以自行下載!
'''
def get_first_url():
  list_href = []
  reaponse = requests.get("http://www.xxx.com.cn", headers=headers)
  soup = Bs4(reaponse.text, "lxml")
  urls_li = soup.select("#mainmenu_top > div > div > ul > li")
  for url_li in urls_li:
    urls = url_li.select("a")
    for url in urls:
      url_href = url.get("href")
      list_href.append(head_url+url_href)
      out_url = list(set(list_href))
  for reg in out_url:
    print(reg)

遍歷第一次返回的結果:

從第二步獲取URL的基礎上,遍歷請求每個頁面,獲取頁面中的URL鏈接,過濾掉不需要的信息

具體代碼如下:

def get_next_url(urllist):
  url_list = []
  for url in urllist:
    response = requests.get(url,headers=headers)
    soup = Bs4(response.text,"lxml")
    urls = soup.find_all("a")
    if urls:
      for url2 in urls:
        url2_1 = url2.get("href")
        if url2_1:
          if url2_1[0] == "/":
            url2_1 = head_url + url2_1
            url_list.append(url2_1)
            if url2_1[0:24] == "http://www.xxx.com.cn":
              url2_1 = url2_1
              url_list.append(url2_1)
            else:
              pass
          else:
            pass
        else:
          pass
    else:
      pass
  url_list2 = set(url_list)
  for url_ in url_list2:
    res = requests.get(url_)
    if res.status_code ==200:
      print(url_)
  print(len(url_list2))

遞歸循環遍歷:

遞歸實現爬取所有url,在get_next_url()函數中調用自身,代碼如下:

get_next_url(url_list2)

全部代碼如下:

import requests
from bs4 import BeautifulSoup as Bs4
 
head_url = "http://www.xxx.com.cn"
headers = {
  "User-Agent": "Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/72.0.3626.121 Safari/537.36"
}
def get_first_url():
  list_href = []
  reaponse = requests.get(head_url, headers=headers)
  soup = Bs4(reaponse.text, "lxml")
  urls_li = soup.select("#mainmenu_top > div > div > ul > li")
  for url_li in urls_li:
    urls = url_li.select("a")
    for url in urls:
      url_href = url.get("href")
      list_href.append(head_url+url_href)
      out_url = list(set(list_href))
  return out_url
 
 
def get_next_url(urllist):
  url_list = []
  for url in urllist:
    response = requests.get(url,headers=headers)
    soup = Bs4(response.text,"lxml")
    urls = soup.find_all("a")
    if urls:
      for url2 in urls:
        url2_1 = url2.get("href")
        if url2_1:
          if url2_1[0] == "/":
            url2_1 = head_url + url2_1
            url_list.append(url2_1)
            if url2_1[0:24] == "http://www.xxx.com.cn":
              url2_1 = url2_1
              url_list.append(url2_1)
            else:
              pass
          else:
            pass
        else:
          pass
    else:
      pass
  url_list2 = set(url_list)
  for url_ in url_list2:
    res = requests.get(url_)
    if res.status_code ==200:
      print(url_)
  print(len(url_list2))
  get_next_url(url_list2)
 
 
if __name__ == "__main__":
  urllist = get_first_url()
  get_next_url(urllist)

最後給大家推薦一個口碑不錯的python聚集地【點擊進入】,這裏有很多的老前輩學習技巧,學習心得

,面試技巧,職場經歷等分享,更爲大家精心準備了零基礎入門資料,實戰項目資料,每天都有程序員

定時講解Python技術,分享一些學習的方法和需要留意的小細節

發表評論
所有評論
還沒有人評論,想成為第一個評論的人麼? 請在上方評論欄輸入並且點擊發布.
相關文章