MySQL 經典練習 50 題(完美解答版)
- 創建數據庫和表
- 經典練習 50 題
- 1、查詢"01"課程比"02"課程成績高的學生的信息及課程分數
- 2、查詢"01"課程比"02"課程成績低的學生的信息及課程分數
- 3、查詢平均成績大於等於60分的同學的學生編號和學生姓名和平均成績
- 4、查詢平均成績小於60分的同學的學生編號和學生姓名和平均成績(包括有成績的和無成績的)
- 5、查詢所有同學的學生編號、學生姓名、選課總數、所有課程的總成績
- 6、查詢"李"姓老師的數量
- 7、詢學過"張三"老師授課的同學的信息
- 8、查詢沒學過"張三"老師授課的同學的信息
- 9、查詢學過編號爲"01"並且也學過編號爲"02"的課程的同學的信息
- 10、查詢學過編號爲"01"但是沒有學過編號爲"02"的課程的同學的信息
- 11、查詢沒有學全所有課程的同學的信息
- 12、查詢至少有一門課與學號爲"01"的同學所學相同的同學的信息
- 13、查詢和"01"號的同學學習的課程完全相同的其他同學的信息
- 14、查詢沒學過"張三"老師講授的任一門課程的學生姓名
- 15、查詢兩門及其以上不及格課程的同學的學號,姓名及其平均成績
- 16、檢索"01"課程分數小於60,按分數降序排列的學生信息
- 17、按平均成績從高到低顯示所有學生的所有課程的成績以及平均成績
- 18、查詢各科成績最高分、最低分和平均分,以如下形式顯示:
- 19、按各科成績進行排序,並顯示排名
- 20、查詢學生的總成績並進行排名
- 21、查詢不同老師所教不同課程平均分從高到低顯示
- 22、查詢所有課程的成績第2名到第3名的學生信息及該課程成績
- 23、統計各科成績各分數段人數:課程編號,課程名稱,[100-85],[85-70],[70-60],[0-60]及所佔百分比
- 24、查詢學生平均成績及其名次
- 25、查詢各科成績前三名的記錄
- 26、查詢每門課程被選修的學生數
- 27、查詢出只有兩門課程的全部學生的學號和姓名
- 28、查詢男生、女生人數
- 29、查詢名字中含有"風"字的學生信息
- 30、查詢同名同性學生名單,並統計同名人數
- 31、查詢1990年出生的學生名單
- 32、查詢每門課程的平均成績,結果按平均成績降序排列,平均成績相同時,按課程編號升序排列
- 33、查詢平均成績大於等於85的所有學生的學號、姓名和平均成績
- 34、查詢課程名稱爲"數學",且分數低於60的學生姓名和分數
- 35、查詢所有學生的課程及分數情況
- 36、查詢任何一門課程成績在70分以上的學生姓名、課程名稱和分數
- 37、查詢課程不及格的學生
- 38、查詢課程編號爲01且課程成績在80分以上的學生的學號和姓名
- 39、求每門課程的學生人數
- 40、查詢選修"張三"老師所授課程的學生中,成績最高的學生信息及其成績
- 41、查詢不同課程成績相同的學生的學生編號、課程編號、學生成績
- 42、查詢每門課程成績最好的前三名
- 43、統計每門課程的學生選修人數(超過5人的課程才統計)
- 44、檢索至少選修兩門課程的學生學號
- 45、查詢選修了全部課程的學生信息
- 46、查詢各學生的年齡(週歲)
- 47、查詢本週過生日的學生
- 48、查詢下週過生日的學生
- 49、查詢本月過生日的學生
- 50、查詢12月份過生日的學生
創建數據庫和表
數據庫
drop database if exists mysql_test cascade;
create database mysql_test;
use mysql_test;
學生表 student
創建學生表 student
create table student (
s_id int,
s_name varchar(8),
s_birth date,
s_sex varchar(4)
);
插入學生數據
insert into student values
(1,'趙雷','1990-01-01','男'),
(2,'錢電','1990-12-21','男'),
(3,'孫風','1990-05-20','男'),
(4,'李雲','1990-08-06','男'),
(5,'周梅','1991-12-01','女'),
(6,'吳蘭','1992-03-01','女'),
(7,'鄭竹','1989-07-01','女'),
(8,'王菊','1990-01-20','女');
課程表 course
創建課程表 course
create table course (
c_id int,
c_name varchar(8),
t_id int
);
插入課程數據
insert into course values
(1,'語文',2),
(2,'數學',1),
(3,'英語',3);
教師表 teacher
創建教師表 teacher
create table teacher (
t_id int,
t_name varchar(8)
);
插入教師數據
insert into teacher values
(1,'張三'),
(2,'李四'),
(3,'王五');
成績表 score
創建成績表 score
create table score (
s_id int,
c_id int,
s_score int
);
插入成績數據
insert into score values
(1,1,80),
(1,2,90),
(1,3,99),
(2,1,70),
(2,2,60),
(2,3,65),
(3,1,80),
(3,2,80),
(3,3,80),
(4,1,50),
(4,2,30),
(4,3,40),
(5,1,76),
(5,2,87),
(6,1,31),
(6,3,34),
(7,2,89),
(7,3,98);
表關係
經典練習 50 題
1、查詢"01"課程比"02"課程成績高的學生的信息及課程分數
select s.*,sc1.s_score as score_01,sc2.s_score as score_02
from student s
inner join (
select * from score where c_id = 1
) sc1
on s.s_id = sc1.s_id
inner join (
select * from score where c_id = 2
) sc2
on s.s_id = sc2.s_id
where sc1.s_score > sc2.s_score;
+------+--------+------------+-------+----------+----------+
| s_id | s_name | s_birth | s_sex | score_01 | score_02 |
+------+--------+------------+-------+----------+----------+
| 2 | 錢電 | 1990-12-21 | 男 | 70 | 60 |
| 4 | 李雲 | 1990-08-06 | 男 | 50 | 30 |
+------+--------+------------+-------+----------+----------+
2、查詢"01"課程比"02"課程成績低的學生的信息及課程分數
select s.*,sc1.s_score as score_01,sc2.s_score as score_02
from student s
inner join (
select * from score where c_id = 1
) sc1
on s.s_id = sc1.s_id
inner join (
select * from score where c_id = 2
) sc2
on s.s_id = sc2.s_id
where sc1.s_score < sc2.s_score;
+------+--------+------------+-------+----------+----------+
| s_id | s_name | s_birth | s_sex | score_01 | score_02 |
+------+--------+------------+-------+----------+----------+
| 1 | 趙雷 | 1990-01-01 | 男 | 80 | 90 |
| 5 | 周梅 | 1991-12-01 | 女 | 76 | 87 |
+------+--------+------------+-------+----------+----------+
3、查詢平均成績大於等於60分的同學的學生編號和學生姓名和平均成績
select s.s_id,s.s_name,round(avg_score, 2) as avg_score
from student s
inner join (
select s_id,avg(s_score) as avg_score
from score
group by s_id
having avg_score >= 60
) t1
on s.s_id = t1.s_id;
+------+--------+-----------+
| s_id | s_name | avg_score |
+------+--------+-----------+
| 1 | 趙雷 | 89.67 |
| 2 | 錢電 | 65.00 |
| 3 | 孫風 | 80.00 |
| 5 | 周梅 | 81.50 |
| 7 | 鄭竹 | 93.50 |
+------+--------+-----------+
4、查詢平均成績小於60分的同學的學生編號和學生姓名和平均成績(包括有成績的和無成績的)
select s.s_id,s.s_name,ifnull(round(avg_score, 2), 0) as avg_score
from student s
left join (
select s_id,avg(s_score) as avg_score
from score
group by s_id
) t1
on s.s_id = t1.s_id
where avg_score is null or avg_score < 60;
+------+--------+-----------+
| s_id | s_name | avg_score |
+------+--------+-----------+
| 4 | 李雲 | 40.00 |
| 6 | 吳蘭 | 32.50 |
| 8 | 王菊 | 0.00 |
+------+--------+-----------+
5、查詢所有同學的學生編號、學生姓名、選課總數、所有課程的總成績
select s.s_id,s.s_name,ifnull(cnt_course, 0) as cnt_course,ifnull(sum_score, 0) as sum_score
from student s
left join (
select s_id,count(*) as cnt_course,sum(s_score) as sum_score
from score
group by s_id
) t1
on s.s_id = t1.s_id;
+------+--------+------------+-----------+
| s_id | s_name | cnt_course | sum_score |
+------+--------+------------+-----------+
| 1 | 趙雷 | 3 | 269 |
| 2 | 錢電 | 3 | 195 |
| 3 | 孫風 | 3 | 240 |
| 4 | 李雲 | 3 | 120 |
| 5 | 周梅 | 2 | 163 |
| 6 | 吳蘭 | 2 | 65 |
| 7 | 鄭竹 | 2 | 187 |
| 8 | 王菊 | 0 | 0 |
+------+--------+------------+-----------+
6、查詢"李"姓老師的數量
select count(*) as cnt_name_li
from teacher
where t_name like '李%';
+-------------+
| cnt_name_li |
+-------------+
| 1 |
+-------------+
7、詢學過"張三"老師授課的同學的信息
select s.*
from student s
where s_id in (
select distinct s_id
from score sc
inner join (
select c_id
from course c
inner join teacher t on c.t_id = t.t_id
where t_name = '張三'
) t1
on sc.c_id = t1.c_id
);
+------+--------+------------+-------+
| s_id | s_name | s_birth | s_sex |
+------+--------+------------+-------+
| 1 | 趙雷 | 1990-01-01 | 男 |
| 2 | 錢電 | 1990-12-21 | 男 |
| 3 | 孫風 | 1990-05-20 | 男 |
| 4 | 李雲 | 1990-08-06 | 男 |
| 5 | 周梅 | 1991-12-01 | 女 |
| 7 | 鄭竹 | 1989-07-01 | 女 |
+------+--------+------------+-------+
8、查詢沒學過"張三"老師授課的同學的信息
select s.*
from student s
where s_id not in (
select distinct s_id
from score sc
inner join (
select c_id
from course c
inner join teacher t on c.t_id = t.t_id
where t_name = '張三'
) t1
on sc.c_id = t1.c_id
);
+------+--------+------------+-------+
| s_id | s_name | s_birth | s_sex |
+------+--------+------------+-------+
| 6 | 吳蘭 | 1992-03-01 | 女 |
| 8 | 王菊 | 1990-01-20 | 女 |
+------+--------+------------+-------+
9、查詢學過編號爲"01"並且也學過編號爲"02"的課程的同學的信息
select s.*
from student s
where s_id in (
select s_id
from score
where c_id in (1,2)
group by s_id
having count(*) = 2
);
+------+--------+------------+-------+
| s_id | s_name | s_birth | s_sex |
+------+--------+------------+-------+
| 1 | 趙雷 | 1990-01-01 | 男 |
| 2 | 錢電 | 1990-12-21 | 男 |
| 3 | 孫風 | 1990-05-20 | 男 |
| 4 | 李雲 | 1990-08-06 | 男 |
| 5 | 周梅 | 1991-12-01 | 女 |
+------+--------+------------+-------+
10、查詢學過編號爲"01"但是沒有學過編號爲"02"的課程的同學的信息
select s.*
from student s
where s_id in (
select s_id
from score
where c_id = 1
and s_id not in (
select s_id from score where c_id = 2
)
);
+------+--------+------------+-------+
| s_id | s_name | s_birth | s_sex |
+------+--------+------------+-------+
| 6 | 吳蘭 | 1992-03-01 | 女 |
+------+--------+------------+-------+
11、查詢沒有學全所有課程的同學的信息
select *
from student
where s_id not in (
select s_id
from score
group by s_id
having count(*) = (
select count(*) from course
)
);
+------+--------+------------+-------+
| s_id | s_name | s_birth | s_sex |
+------+--------+------------+-------+
| 5 | 周梅 | 1991-12-01 | 女 |
| 6 | 吳蘭 | 1992-03-01 | 女 |
| 7 | 鄭竹 | 1989-07-01 | 女 |
| 8 | 王菊 | 1990-01-20 | 女 |
+------+--------+------------+-------+
12、查詢至少有一門課與學號爲"01"的同學所學相同的同學的信息
select *
from student
where s_id in (
select distinct s_id
from score s
inner join (
select c_id from score where s_id = 1
) t1
on s.c_id = t1.c_id
);
+------+--------+------------+-------+
| s_id | s_name | s_birth | s_sex |
+------+--------+------------+-------+
| 1 | 趙雷 | 1990-01-01 | 男 |
| 2 | 錢電 | 1990-12-21 | 男 |
| 3 | 孫風 | 1990-05-20 | 男 |
| 4 | 李雲 | 1990-08-06 | 男 |
| 5 | 周梅 | 1991-12-01 | 女 |
| 6 | 吳蘭 | 1992-03-01 | 女 |
| 7 | 鄭竹 | 1989-07-01 | 女 |
+------+--------+------------+-------+
13、查詢和"01"號的同學學習的課程完全相同的其他同學的信息
select *
from student
where s_id in (
select s_id
from score s
inner join (
select c_id from score where s_id = 1
) t1
on s.c_id = t1.c_id
where s_id != 1
group by s_idhaving count(*) = (
select count(*) from score where s_id = 1
)
);
+------+--------+------------+-------+
| s_id | s_name | s_birth | s_sex |
+------+--------+------------+-------+
| 2 | 錢電 | 1990-12-21 | 男 |
| 3 | 孫風 | 1990-05-20 | 男 |
| 4 | 李雲 | 1990-08-06 | 男 |
+------+--------+------------+-------+
14、查詢沒學過"張三"老師講授的任一門課程的學生姓名
select s_name
from student
where s_id not in (
select s_id
from score sc
inner join (
select c_id
from course c
inner join teacher t on c.t_id = t.t_id
where t_name = '張三'
) t1
on sc.c_id = t1.c_id
);
+--------+
| s_name |
+--------+
| 吳蘭 |
| 王菊 |
+--------+
15、查詢兩門及其以上不及格課程的同學的學號,姓名及其平均成績
select s.s_id,s.s_name,round(avg(s_score), 2) as avg_score
from student s
inner join (
select s_id
from score
where s_score < 60
group by s_id
having count(*) >= 2
) t1
on s.s_id = t1.s_id
inner join score sc on s.s_id = sc.s_id
group by s.s_id;
+------+--------+-----------+
| s_id | s_name | avg_score |
+------+--------+-----------+
| 4 | 李雲 | 40.00 |
| 6 | 吳蘭 | 32.50 |
+------+--------+-----------+
16、檢索"01"課程分數小於60,按分數降序排列的學生信息
select s.*,s_score as score_01
from student s
inner join (
select s_id,s_score
from score
where c_id = 1
and s_score < 60
) t1
on s.s_id = t1.s_id
order by score_01 desc;
+------+--------+------------+-------+----------+
| s_id | s_name | s_birth | s_sex | score_01 |
+------+--------+------------+-------+----------+
| 4 | 李雲 | 1990-08-06 | 男 | 50 |
| 6 | 吳蘭 | 1992-03-01 | 女 | 31 |
+------+--------+------------+-------+----------+
17、按平均成績從高到低顯示所有學生的所有課程的成績以及平均成績
select
s.s_id as 學號,s.s_name as 姓名,
sum(case c_id when 1 then s_score else 0 end) as 語文,
sum(case c_id when 2 then s_score else 0 end) as 數學,
sum(case c_id when 3 then s_score else 0 end) as 英語,
ifnull(round(avg(s_score), 2), 0) as 平均成績
from student s
left join score sc on s.s_id = sc.s_id
group by s.s_id
order by 平均成績 desc;
+------+------+------+------+------+----------+
| 學號 | 姓名 | 語文 | 數學 | 英語 | 平均成績 |
+------+------+------+------+------+----------+
| 7 | 鄭竹 | 0 | 89 | 98 | 93.50 |
| 1 | 趙雷 | 80 | 90 | 99 | 89.67 |
| 5 | 周梅 | 76 | 87 | 0 | 81.50 |
| 3 | 孫風 | 80 | 80 | 80 | 80.00 |
| 2 | 錢電 | 70 | 60 | 65 | 65.00 |
| 4 | 李雲 | 50 | 30 | 40 | 40.00 |
| 6 | 吳蘭 | 31 | 0 | 34 | 32.50 |
| 8 | 王菊 | 0 | 0 | 0 | 0.00 |
+------+------+------+------+------+----------+
18、查詢各科成績最高分、最低分和平均分,以如下形式顯示:
課程ID,課程name,最高分,最低分,平均分,及格率,中等率,優良率,優秀率
– 及格爲>=60,中等爲:70-80,優良爲:80-90,優秀爲:>=90
select
c.c_id as 課程ID,c.c_name as 課程name,
max(s_score) as 最高分,
min(s_score) as 最低分,
round(avg(s_score), 2) as 平均分,
concat(round(sum(case when s_score >= 60 then 1 else 0 end) / count(*) * 100, 2), '%') as 及格率,
concat(round(sum(case when s_score between 70 and 80 then 1 else 0 end) / count(*) * 100, 2), '%') as 中等率,
concat(round(sum(case when s_score between 80 and 90 then 1 else 0 end) / count(*) * 100, 2), '%') as 優良率,
concat(round(sum(case when s_score >= 90 then 1 else 0 end) / count(*) * 100, 2), '%') as 優秀率
from course c
inner join score s on c.c_id = s.c_id
group by c.c_id;
+--------+----------+--------+--------+--------+--------+--------+--------+--------+
| 課程ID | 課程name | 最高分 | 最低分 | 平均分 | 及格率 | 中等率 | 優良率 | 優秀率 |
+--------+----------+--------+--------+--------+--------+--------+--------+--------+
| 1 | 語文 | 80 | 31 | 64.50 | 66.67% | 66.67% | 33.33% | 0.00% |
| 2 | 數學 | 90 | 30 | 72.67 | 83.33% | 16.67% | 66.67% | 16.67% |
| 3 | 英語 | 99 | 34 | 69.33 | 66.67% | 16.67% | 16.67% | 33.33% |
+--------+----------+--------+--------+--------+--------+--------+--------+--------+
19、按各科成績進行排序,並顯示排名
select
(@i := case when @pre_group_id = c_id then @i + 1 else 1 end) as rank,
(@pre_group_id := c_id) as c_id,
c_name,s_id,s_name,s_score
from (select @i := 0, @pre_group_id := 1) var
cross join (
select c.c_id,c.c_name,s.s_id,s.s_name,s_score
from score sc
inner join student s on sc.s_id = s.s_id
inner join course c on sc.c_id = c.c_id
group by c.c_id,s.s_id
order by c.c_id,s_score desc
) t1;
+------+------+--------+------+--------+---------+
| rank | c_id | c_name | s_id | s_name | s_score |
+------+------+--------+------+--------+---------+
| 1 | 1 | 語文 | 1 | 趙雷 | 80 |
| 2 | 1 | 語文 | 3 | 孫風 | 80 |
| 3 | 1 | 語文 | 5 | 周梅 | 76 |
| 4 | 1 | 語文 | 2 | 錢電 | 70 |
| 5 | 1 | 語文 | 4 | 李雲 | 50 |
| 6 | 1 | 語文 | 6 | 吳蘭 | 31 |
| 1 | 2 | 數學 | 1 | 趙雷 | 90 |
| 2 | 2 | 數學 | 7 | 鄭竹 | 89 |
| 3 | 2 | 數學 | 5 | 周梅 | 87 |
| 4 | 2 | 數學 | 3 | 孫風 | 80 |
| 5 | 2 | 數學 | 2 | 錢電 | 60 |
| 6 | 2 | 數學 | 4 | 李雲 | 30 |
| 1 | 3 | 英語 | 1 | 趙雷 | 99 |
| 2 | 3 | 英語 | 7 | 鄭竹 | 98 |
| 3 | 3 | 英語 | 3 | 孫風 | 80 |
| 4 | 3 | 英語 | 2 | 錢電 | 65 |
| 5 | 3 | 英語 | 4 | 李雲 | 40 |
| 6 | 3 | 英語 | 6 | 吳蘭 | 34 |
+------+------+--------+------+--------+---------+
20、查詢學生的總成績並進行排名
select (@i := @i + 1) as rank,t2.*
from (select @i := 0) var
cross join (
select s.s_id,s.s_name,sum_score
from student s
inner join (
select s_id,sum(s_score) as sum_score
from score
group by s_id
) t1
on s.s_id = t1.s_id
order by sum_score desc
) t2;
+------+------+--------+-----------+
| rank | s_id | s_name | sum_score |
+------+------+--------+-----------+
| 1 | 1 | 趙雷 | 269 |
| 2 | 3 | 孫風 | 240 |
| 3 | 2 | 錢電 | 195 |
| 4 | 7 | 鄭竹 | 187 |
| 5 | 5 | 周梅 | 163 |
| 6 | 4 | 李雲 | 120 |
| 7 | 6 | 吳蘭 | 65 |
+------+------+--------+-----------+
21、查詢不同老師所教不同課程平均分從高到低顯示
select t.t_id,t.t_name,c.c_id,c.c_name,round(avg(s_score), 2) as avg_score
from score sc
inner join course c on sc.c_id = c.c_id
inner join teacher t on t.t_id = c.t_id
group by t.t_id,c.c_id
order by t.t_id,avg_score desc;
+------+--------+------+--------+-----------+
| t_id | t_name | c_id | c_name | avg_score |
+------+--------+------+--------+-----------+
| 1 | 張三 | 2 | 數學 | 72.67 |
| 2 | 李四 | 1 | 語文 | 64.50 |
| 3 | 王五 | 3 | 英語 | 69.33 |
+------+--------+------+--------+-----------+
22、查詢所有課程的成績第2名到第3名的學生信息及該課程成績
select *
from (
select
(@i := case when @pre_group_id = c_id then @i + 1 else 1 end) as rank,
(@pre_group_id := c_id) as c_id,
c_name,s_id,s_name,s_birth,s_sex,s_score
from (select @i := 0, @pre_group_id := 1) var
cross join (
select c.c_id,c.c_name,s.*,s_score
from score sc
inner join student s on sc.s_id = s.s_id
inner join course c on sc.c_id = c.c_id
group by c.c_id,s.s_id
order by c.c_id,s_score desc
) t1
) t2
where rank in (2,3);
+------+------+--------+------+--------+------------+-------+---------+
| rank | c_id | c_name | s_id | s_name | s_birth | s_sex | s_score |
+------+------+--------+------+--------+------------+-------+---------+
| 2 | 1 | 語文 | 3 | 孫風 | 1990-05-20 | 男 | 80 |
| 3 | 1 | 語文 | 5 | 周梅 | 1991-12-01 | 女 | 76 |
| 2 | 2 | 數學 | 7 | 鄭竹 | 1989-07-01 | 女 | 89 |
| 3 | 2 | 數學 | 5 | 周梅 | 1991-12-01 | 女 | 87 |
| 2 | 3 | 英語 | 7 | 鄭竹 | 1989-07-01 | 女 | 98 |
| 3 | 3 | 英語 | 3 | 孫風 | 1990-05-20 | 男 | 80 |
+------+------+--------+------+--------+------------+-------+---------+
23、統計各科成績各分數段人數:課程編號,課程名稱,[100-85],[85-70],[70-60],[0-60]及所佔百分比
select
c.c_id as 課程編號,c.c_name as 課程名稱,
sum(case when s_score between 85 and 100 then 1 else 0 end) as '[100-85]',
concat(round(sum(case when s_score between 85 and 100 then 1 else 0 end) / count(*) * 100, 2), '%') as 百分比,
sum(case when s_score between 70 and 85 then 1 else 0 end) as '[85-70]',
concat(round(sum(case when s_score between 70 and 85 then 1 else 0 end) / count(*) * 100, 2), '%') as 百分比,
sum(case when s_score between 60 and 70 then 1 else 0 end) as '[70-60]',
concat(round(sum(case when s_score between 60 and 70 then 1 else 0 end) / count(*) * 100, 2), '%') as 百分比,
sum(case when s_score between 0 and 60 then 1 else 0 end) as '[0-60]',
concat(round(sum(case when s_score between 0 and 60 then 1 else 0 end) / count(*) * 100, 2), '%') as 百分比
from course c
inner join score sc
on c.c_id = sc.c_id
group by c.c_id;
+----------+----------+----------+--------+---------+--------+---------+--------+--------+--------+
| 課程編號 | 課程名稱 | [100-85] | 百分比 | [85-70] | 百分比 | [70-60] | 百分比 | [0-60] | 百分比 |
+----------+----------+----------+--------+---------+--------+---------+--------+--------+--------+
| 1 | 語文 | 0 | 0.00% | 4 | 66.67% | 1 | 16.67% | 2 | 33.33% |
| 2 | 數學 | 3 | 50.00% | 1 | 16.67% | 1 | 16.67% | 2 | 33.33% |
| 3 | 英語 | 2 | 33.33% | 1 | 16.67% | 1 | 16.67% | 2 | 33.33% |
+----------+----------+----------+--------+---------+--------+---------+--------+--------+--------+
24、查詢學生平均成績及其名次
select (@i := @i + 1) as rank,t2.*
from (select @i := 0) var
cross join (
select s.s_id,s.s_name,avg_score
from student s
inner join (
select s_id,round(avg(s_score), 2) as avg_score
from score
group by s_id
) t1
on s.s_id = t1.s_id
order by avg_score desc
) t2;
+------+------+--------+-----------+
| rank | s_id | s_name | avg_score |
+------+------+--------+-----------+
| 1 | 7 | 鄭竹 | 93.50 |
| 2 | 1 | 趙雷 | 89.67 |
| 3 | 5 | 周梅 | 81.50 |
| 4 | 3 | 孫風 | 80.00 |
| 5 | 2 | 錢電 | 65.00 |
| 6 | 4 | 李雲 | 40.00 |
| 7 | 6 | 吳蘭 | 32.50 |
+------+------+--------+-----------+
25、查詢各科成績前三名的記錄
方法 1:內外關聯
select c.c_id,c.c_name,s.s_id,s.s_name,s_score
from (
select *
from score sc
where (
select count(*)
from score sc1
where sc.c_id = sc1.c_id
and sc.s_score < sc1.s_score
) < 3
)
t1
inner join student s on t1.s_id = s.s_id
inner join course c on t1.c_id = c.c_id
order by c.c_id,s_score desc;
+------+--------+------+--------+---------+
| c_id | c_name | s_id | s_name | s_score |
+------+--------+------+--------+---------+
| 1 | 語文 | 1 | 趙雷 | 80 |
| 1 | 語文 | 3 | 孫風 | 80 |
| 1 | 語文 | 5 | 周梅 | 76 |
| 2 | 數學 | 1 | 趙雷 | 90 |
| 2 | 數學 | 7 | 鄭竹 | 89 |
| 2 | 數學 | 5 | 周梅 | 87 |
| 3 | 英語 | 1 | 趙雷 | 99 |
| 3 | 英語 | 7 | 鄭竹 | 98 |
| 3 | 英語 | 3 | 孫風 | 80 |
+------+--------+------+--------+---------+
方法 2:序號篩選
select *
from (
select
(@i := case when @pre_group_id = c_id then @i + 1 else 1 end) as rank,
(@pre_group_id := c_id) as c_id,
c_name,s_id,s_name,s_score
from (select @i := 0, @pre_group_id := 1) var
cross join (
select c.c_id,c.c_name,s.s_id,s.s_name,s_score
from score sc
inner join student s on sc.s_id = s.s_id
inner join course c on sc.c_id = c.c_id
group by c.c_id,s.s_id
order by c.c_id,s_score desc
) t1
) t2
where rank <= 3;
+------+------+--------+------+--------+---------+
| rank | c_id | c_name | s_id | s_name | s_score |
+------+------+--------+------+--------+---------+
| 1 | 1 | 語文 | 1 | 趙雷 | 80 |
| 2 | 1 | 語文 | 3 | 孫風 | 80 |
| 3 | 1 | 語文 | 5 | 周梅 | 76 |
| 1 | 2 | 數學 | 1 | 趙雷 | 90 |
| 2 | 2 | 數學 | 7 | 鄭竹 | 89 |
| 3 | 2 | 數學 | 5 | 周梅 | 87 |
| 1 | 3 | 英語 | 1 | 趙雷 | 99 |
| 2 | 3 | 英語 | 7 | 鄭竹 | 98 |
| 3 | 3 | 英語 | 3 | 孫風 | 80 |
+------+------+--------+------+--------+---------+
26、查詢每門課程被選修的學生數
select c.c_id,c.c_name,cnt_student
from course c
inner join (
select c_id,count(*) as cnt_student
from score
group by c_id
) t1
on c.c_id = t1.c_id;
+------+--------+-------------+
| c_id | c_name | cnt_student |
+------+--------+-------------+
| 1 | 語文 | 6 |
| 2 | 數學 | 6 |
| 3 | 英語 | 6 |
+------+--------+-------------+
27、查詢出只有兩門課程的全部學生的學號和姓名
select s_id,s_name
from student
where s_id in (
select s_id
from score
group by s_id
having count(*) = 2
);
+------+--------+
| s_id | s_name |
+------+--------+
| 5 | 周梅 |
| 6 | 吳蘭 |
| 7 | 鄭竹 |
+------+--------+
28、查詢男生、女生人數
select s_sex,count(*) as cnt_sex
from student
group by s_sex;
+-------+---------+
| s_sex | cnt_sex |
+-------+---------+
| 女 | 4 |
| 男 | 4 |
+-------+---------+
29、查詢名字中含有"風"字的學生信息
select *
from student
where s_name like '%風%';
+------+--------+------------+-------+
| s_id | s_name | s_birth | s_sex |
+------+--------+------------+-------+
| 3 | 孫風 | 1990-05-20 | 男 |
+------+--------+------------+-------+
30、查詢同名同性學生名單,並統計同名人數
select *,count(*) as cnt_student
from student
group by s_name,s_sex
having cnt_student > 1;
+-----------+
| Empty set |
+-----------+
31、查詢1990年出生的學生名單
select *
from student
where year(s_birth) = '1990';
+------+--------+------------+-------+
| s_id | s_name | s_birth | s_sex |
+------+--------+------------+-------+
| 1 | 趙雷 | 1990-01-01 | 男 |
| 2 | 錢電 | 1990-12-21 | 男 |
| 3 | 孫風 | 1990-05-20 | 男 |
| 4 | 李雲 | 1990-08-06 | 男 |
| 8 | 王菊 | 1990-01-20 | 女 |
+------+--------+------------+-------+
32、查詢每門課程的平均成績,結果按平均成績降序排列,平均成績相同時,按課程編號升序排列
select c.c_id,c.c_name,avg_score
from course c
inner join (
select c_id,round(avg(s_score), 2) as avg_score
from score
group by c_id
) t1
on c.c_id = t1.c_id
order by avg_score desc,c.c_id;
+------+--------+-----------+
| c_id | c_name | avg_score |
+------+--------+-----------+
| 2 | 數學 | 72.67 |
| 3 | 英語 | 69.33 |
| 1 | 語文 | 64.50 |
+------+--------+-----------+
33、查詢平均成績大於等於85的所有學生的學號、姓名和平均成績
select s.s_id,s.s_name,avg_score
from student s
inner join (
select s_id,round(avg(s_score), 2) as avg_score
from score
group by s_id
having avg_score >= 85
) t1
on s.s_id = t1.s_id;
+------+--------+-----------+
| s_id | s_name | avg_score |
+------+--------+-----------+
| 1 | 趙雷 | 89.67 |
| 7 | 鄭竹 | 93.50 |
+------+--------+-----------+
34、查詢課程名稱爲"數學",且分數低於60的學生姓名和分數
select s_name,s_score
from student s
inner join (
select s_id,s_score
from score sc
inner join course c on sc.c_id = c.c_id
where c_name = '數學'
and s_score < 60
) t1
on s.s_id = t1.s_id;
+--------+---------+
| s_name | s_score |
+--------+---------+
| 李雲 | 30 |
+--------+---------+
35、查詢所有學生的課程及分數情況
select
s.s_id,s.s_name,
sum(case c_id when 1 then s_score else 0 end) as 語文,
sum(case c_id when 2 then s_score else 0 end) as 數學,
sum(case c_id when 3 then s_score else 0 end) as 英語
from student s
left join score sc on s.s_id = sc.s_id
group by s.s_id;
+------+--------+------+------+------+
| s_id | s_name | 語文 | 數學 | 英語 |
+------+--------+------+------+------+
| 1 | 趙雷 | 80 | 90 | 99 |
| 2 | 錢電 | 70 | 60 | 65 |
| 3 | 孫風 | 80 | 80 | 80 |
| 4 | 李雲 | 50 | 30 | 40 |
| 5 | 周梅 | 76 | 87 | 0 |
| 6 | 吳蘭 | 31 | 0 | 34 |
| 7 | 鄭竹 | 0 | 89 | 98 |
| 8 | 王菊 | 0 | 0 | 0 |
+------+--------+------+------+------+
36、查詢任何一門課程成績在70分以上的學生姓名、課程名稱和分數
select s_name,c_name,s_score
from score sc
inner join student s on sc.s_id = s.s_id
inner join course c on sc.c_id = c.c_id
where s_score > 70
group by s.s_id;
+--------+--------+---------+
| s_name | c_name | s_score |
+--------+--------+---------+
| 趙雷 | 語文 | 80 |
| 孫風 | 語文 | 80 |
| 周梅 | 語文 | 76 |
| 鄭竹 | 數學 | 89 |
+--------+--------+---------+
37、查詢課程不及格的學生
select s.s_id,s.s_name,c.c_id,c.c_name,s_score
from score sc
inner join student s on sc.s_id = s.s_id
inner join course c on sc.c_id = c.c_id
where s_score < 60;
+------+--------+------+--------+---------+
| s_id | s_name | c_id | c_name | s_score |
+------+--------+------+--------+---------+
| 4 | 李雲 | 1 | 語文 | 50 |
| 4 | 李雲 | 2 | 數學 | 30 |
| 4 | 李雲 | 3 | 英語 | 40 |
| 6 | 吳蘭 | 1 | 語文 | 31 |
| 6 | 吳蘭 | 3 | 英語 | 34 |
+------+--------+------+--------+---------+
38、查詢課程編號爲01且課程成績在80分以上的學生的學號和姓名
select s.s_id,s.s_name
from student s
where s_id in (
select s_id
from score
where c_id = 1
and s_score >= 80
);
+------+--------+
| s_id | s_name |
+------+--------+
| 1 | 趙雷 |
| 3 | 孫風 |
+------+--------+
39、求每門課程的學生人數
select c.c_id,c.c_name,cnt_student
from course c
inner join (
select c_id,count(*) as cnt_student
from score
group by c_id
) t1
on c.c_id = t1.c_id;
+------+--------+-------------+
| c_id | c_name | cnt_student |
+------+--------+-------------+
| 1 | 語文 | 6 |
| 2 | 數學 | 6 |
| 3 | 英語 | 6 |
+------+--------+-------------+
40、查詢選修"張三"老師所授課程的學生中,成績最高的學生信息及其成績
select s.*,s_score as max_score
from student s
inner join (
select s_id,s_score
from score sc
inner join (
select c_id
from course c
inner join teacher t on c.t_id = t.t_id
where t_name = '張三'
) t1
on sc.c_id = t1.c_id
order by s_score desc
limit 1
) t2
on s.s_id = t2.s_id;
+------+--------+------------+-------+-----------+
| s_id | s_name | s_birth | s_sex | max_score |
+------+--------+------------+-------+-----------+
| 1 | 趙雷 | 1990-01-01 | 男 | 90 |
+------+--------+------------+-------+-----------+
41、查詢不同課程成績相同的學生的學生編號、課程編號、學生成績
select *
from score
where s_score in (
select s_score
from score
group by s_score
having count(*) > 1
);
+------+------+---------+
| s_id | c_id | s_score |
+------+------+---------+
| 1 | 1 | 80 |
| 3 | 1 | 80 |
| 3 | 2 | 80 |
| 3 | 3 | 80 |
+------+------+---------+
42、查詢每門課程成績最好的前三名
方法 1:內外關聯
select c.c_id,c.c_name,s.s_id,s.s_name,s_score
from (
select *
from score sc
where (
select count(*)
from score sc1
where sc.c_id = sc1.c_id
and sc.s_score < sc1.s_score
) < 3
) t1
inner join student s on t1.s_id = s.s_id
inner join course c on t1.c_id = c.c_id
order by c.c_id,s_score desc;
+------+--------+------+--------+---------+
| c_id | c_name | s_id | s_name | s_score |
+------+--------+------+--------+---------+
| 1 | 語文 | 1 | 趙雷 | 80 |
| 1 | 語文 | 3 | 孫風 | 80 |
| 1 | 語文 | 5 | 周梅 | 76 |
| 2 | 數學 | 1 | 趙雷 | 90 |
| 2 | 數學 | 7 | 鄭竹 | 89 |
| 2 | 數學 | 5 | 周梅 | 87 |
| 3 | 英語 | 1 | 趙雷 | 99 |
| 3 | 英語 | 7 | 鄭竹 | 98 |
| 3 | 英語 | 3 | 孫風 | 80 |
+------+--------+------+--------+---------+
方法 2:序號篩選
select *
from (
select
(@i := case when @pre_group_id = c_id then @i + 1 else 1 end) as rank,
(@pre_group_id := c_id) as c_id,
c_name,s_id,s_name,s_score
from (select @i := 0, @pre_group_id := 1) var
cross join (
select c.c_id,c.c_name,s.s_id,s.s_name,s_score
from score sc
inner join student s on sc.s_id = s.s_id
inner join course c on sc.c_id = c.c_id
group by c.c_id,s.s_id
order by c.c_id,s_score desc
) t1
) t2
where rank <= 3;
+------+------+--------+------+--------+---------+
| rank | c_id | c_name | s_id | s_name | s_score |
+------+------+--------+------+--------+---------+
| 1 | 1 | 語文 | 1 | 趙雷 | 80 |
| 2 | 1 | 語文 | 3 | 孫風 | 80 |
| 3 | 1 | 語文 | 5 | 周梅 | 76 |
| 1 | 2 | 數學 | 1 | 趙雷 | 90 |
| 2 | 2 | 數學 | 7 | 鄭竹 | 89 |
| 3 | 2 | 數學 | 5 | 周梅 | 87 |
| 1 | 3 | 英語 | 1 | 趙雷 | 99 |
| 2 | 3 | 英語 | 7 | 鄭竹 | 98 |
| 3 | 3 | 英語 | 3 | 孫風 | 80 |
+------+------+--------+------+--------+---------+
43、統計每門課程的學生選修人數(超過5人的課程才統計)
– 要求輸出課程號和選修人數,查詢結果按人數降序排列,若人數相同,按課程號升序排列
select c.c_id,cnt_student
from course c
inner join (
select c_id,count(*) as cnt_student
from score
group by c_id
having cnt_student > 5
) t1
on c.c_id = t1.c_id
order by cnt_student desc,c.c_id;
+------+-------------+
| c_id | cnt_student |
+------+-------------+
| 1 | 6 |
| 2 | 6 |
| 3 | 6 |
+------+-------------+
44、檢索至少選修兩門課程的學生學號
select s_id
from score
group by s_id
having count(*) >= 2;
+------+
| s_id |
+------+
| 1 |
| 2 |
| 3 |
| 4 |
| 5 |
| 6 |
| 7 |
+------+
45、查詢選修了全部課程的學生信息
select *
from student
where s_id in (
select s_id
from score
group by s_id
having count(*) = (
select count(*) from course
)
);
+------+--------+------------+-------+
| s_id | s_name | s_birth | s_sex |
+------+--------+------------+-------+
| 1 | 趙雷 | 1990-01-01 | 男 |
| 2 | 錢電 | 1990-12-21 | 男 |
| 3 | 孫風 | 1990-05-20 | 男 |
| 4 | 李雲 | 1990-08-06 | 男 |
+------+--------+------------+-------+
46、查詢各學生的年齡(週歲)
– 按照出生日期來算,當前月日 < 出生年月的月日則,年齡減一
select
s_id,s_name,s_birth,
if (
month(current_date()) < month(s_birth) or (month(current_date()) = month(s_birth) and day(current_date()) < day(s_birth)),
year(current_date()) - year(s_birth) -1,
year(current_date()) - year(s_birth)
)
as s_age
from student;
47、查詢本週過生日的學生
select *
from student
where
datediff(concat(year(current_date()), date_format(s_birth, '-%m-%d')), current_date())
between 0 and 7
or
datediff(concat(year(current_date()) + 1, date_format(s_birth, '-%m-%d')), current_date())
between 0 and 7;
48、查詢下週過生日的學生
select *
from student
where
datediff(concat(year(current_date()), date_format(s_birth, '-%m-%d')), current_date())
between 7 and 14
or
datediff(concat(year(current_date()) + 1, date_format(s_birth, '-%m-%d')), current_date())
between 7 and 14;
49、查詢本月過生日的學生
select *
from student
where month(s_birth) = month(current_date());
50、查詢12月份過生日的學生
select *
from student
where month(s_birth) = 12;
+------+--------+------------+-------+
| s_id | s_name | s_birth | s_sex |
+------+--------+------------+-------+
| 2 | 錢電 | 1990-12-21 | 男 |
| 5 | 周梅 | 1991-12-01 | 女 |
+------+--------+------------+-------+