將隨機數量的用最小旋轉矩形包圍

#include <iostream>
#include <opencv2/opencv.hpp>


using namespace cv;
using namespace std;



#define window "【原始圖】"
#define windowx "【結果圖1】"
#define windowy "[結果圖2]"
//將隨機數量的用最小旋轉矩形包圍。



void on_thresh(int,void*);
int main()
{

	

	Mat image(Size(600,600),CV_8UC3);
	RNG rng = theRNG();
	while (1)
	{
		
		int count = rng.uniform(3, 103);
		vector<Point> points;
		int x, y;
		for (int i = 0; i < count; ++i)
		{
			 x = rng.uniform(100, 500);
			 y = rng.uniform(100, 500);
			points.push_back(Point(x, y));
		}

		


		RotatedRect rect = minAreaRect(points);//xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx最小旋轉矩形。
		Point2f po[4];
		rect.points(po);//xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx將rect的四個定點提取出來。
		Point pre = po[3];
		Mat result(image.size(), image.type(),Scalar(0));

		for (int i = 0; i < count; ++i)
		{
			circle(result, points[i], 3, Scalar(rng.uniform(0, 255), rng.uniform(0, 255), rng.uniform(0, 255)), -1);

		}
		for (int i = 0; i < 4; ++i)
		{
			line(result, pre, po[i], Scalar(rng.uniform(0, 255),rng.uniform(0,255),rng.uniform(0,255)));
			pre = po[i];
		}

		imshow(windowx, result);

		int ch = waitKey(0);
		if (ch == 27) break;

	}
	waitKey(0);
	return 0;

}