【LeetCode 1371】 Find the Longest Substring Containing Vowels in Even Counts

题目描述

Given the string s, return the size of the longest substring containing each vowel an even number of times. That is, ‘a’, ‘e’, ‘i’, ‘o’, and ‘u’ must appear an even number of times.

Example 1:

Input: s = "eleetminicoworoep"
Output: 13
Explanation: The longest substring is "leetminicowor" which contains two each of the vowels: e, i and o and zero of the vowels: a and u.

Example 2:

Input: s = "leetcodeisgreat"
Output: 5
Explanation: The longest substring is "leetc" which contains two e's.

Example 3:

Input: s = "bcbcbc"
Output: 6
Explanation: In this case, the given string "bcbcbc" is the longest because all vowels: a, e, i, o and u appear zero times.

Constraints:

1 <= s.length <= 5 x 10^5
s contains only lowercase English letters.

思路

状态压缩,用2^5位标记每个元音当前个数的奇偶情况mask,当前位置和该mask上次出现的位置之差,就是符合的字符串长度。

代码

class Solution {
public:
    int findTheLongestSubstring(string s) {
        int n = s.length();
        char c[5] = {'a', 'e', 'i', 'o', 'u'};
        vector<int> h(32, n+1);
        h[0] = -1;
        int mask = 0;
        int ans = 0;
        
        for (int i=0; i<n; ++i) {
            for (int j=0; j<5; ++j) {
                if (s[i] == c[j]) {
                    mask ^= (1<<j);
                }
            }
            ans = max(ans, i - h[mask]);
            h[mask] = min(h[mask], i);
        }
        
        return ans;
    }
};
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