一天一天算日期~

計算a年b月c日到x年y月z日之間的天數

以2008,8,8爲例:

/*************************************************************************
        > File Name: 2519.cpp
      > Author: dulun
      > Mail: [email protected]
      > Created Time: 2016年08月28日 星期日 12時53分40秒
 ************************************************************************/

#include<iostream>
#include<stdio.h>
#include<string.h>
#include<stdlib.h>
#include<algorithm>
#define LL long long
using namespace std;

const int N = 50086;

int list[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};

int main()
{
    int year;
    int month;
    int day;
    int sum = 0;

    scanf("%d%d%d", &year, &month, &day);

    int k = month;
    int i = day;


    for(int l = year; l <= 2008; l++)
    {
        if((l % 4 == 0 && l % 100 != 0) || l % 400 == 0)
        {
            list[2] = 29;
        }
        else{
            list[2] = 28;
        }

        for(; k <= 12; k++)
        {
            for(; i <= list[k]; i++)
            {
                if( l == 2008 && k == 8 && i == 8 )
                    return !printf("%d\n", sum);
                sum ++;
            }
            i = 1;
        }
        k = 1;
    }
}