IOS-sql語句中遇到的字符串拼接

//費了不少時間啊

NSArray *arr = @[@"a",@"b",@"c"];
    NSString *string00  = @"select * from %@ in %@ with %@";
    for (NSString *str in arr) {
        if ([string00 rangeOfString:@"%@"].location!=NSNotFound) {
            NSRange rang = [string00 rangeOfString:@"%@"];
            string00 = [string00 stringByReplacingCharactersInRange:NSMakeRange(rang.location, 2) withString:str];
        }
    }
    //string00------select * from a in b with c