George has recently entered the BSUCP (Berland State University for Cool Programmers). George has a friend Alex who has also entered the university. Now they are moving into a dormitory.
George and Alex want to live in the same room. The dormitory has n rooms in total. At the moment the i-th room has pi people living in it and the room can accommodate qi people in total (pi ≤ qi). Your task is to count how many rooms has free place for both George and Alex.
The first line contains a single integer n (1 ≤ n ≤ 100) — the number of rooms.
The i-th of the next n lines contains two integers pi and qi (0 ≤ pi ≤ qi ≤ 100) — the number of people who already live in the i-th room and the room's capacity.
Print a single integer — the number of rooms where George and Alex can move in.
3 1 1 2 2 3 3
0
3 1 10 0 10 10 10
2
AC:
#include<bits/stdc++.h>
using namespace std;
int main()
{
int n;
scanf("%d",&n);
int p[110],q[110],cha[110];
for(int i=0;i<n;i++)
{
scanf("%d%d",p+i,q+i);
cha[i]=q[i]-p[i];
}
int ans=0;
for(int i=0;i<n;i++)
if(cha[i]>=2)
ans++;
printf("%d\n",ans);
}