- js計算精度問題
- ie下forEach不支持問題
- 數組去重複問題
<script type="text/javascript">
function add(a, b) {
var c, d, e;
try {
c = a.toString().split(".")[1].length;
} catch (f) {
c = 0;
}
try {
d = b.toString().split(".")[1].length;
} catch (f) {
d = 0;
}
return e = Math.pow(10, Math.max(c, d)), (mul(a, e) + mul(b, e)) / e;
}
function sub(a, b) {
var c, d, e;
try {
c = a.toString().split(".")[1].length;
} catch (f) {
c = 0;
}
try {
d = b.toString().split(".")[1].length;
} catch (f) {
d = 0;
}
return e = Math.pow(10, Math.max(c, d)), (mul(a, e) - mul(b, e)) / e;
}
function mul(a, b) {
var c = 0,
d = a.toString(),
e = b.toString();
try {
c += d.split(".")[1].length;
} catch (f) { }
try {
c += e.split(".")[1].length;
} catch (f) { }
return Number(d.replace(".", "")) * Number(e.replace(".", "")) / Math.pow(10, c);
}
function div(a, b) {
var c, d, e = 0,
f = 0;
try {
e = a.toString().split(".")[1].length;
} catch (g) { }
try {
f = b.toString().split(".")[1].length;
} catch (g) { }
return c = Number(a.toString().replace(".", "")), d = Number(b.toString().replace(".", "")), mul(c / d, Math.pow(10, f - e));
}
function uniArr(arr) {
var new_arr = [];
for (var i = 0; i < arr.length; i++) {
var items = arr[i];
if ($.inArray(items, new_arr) == -1) {
new_arr.push(items);
}
}
return new_arr;
}
Array.prototype.forEach = function forEach(callback, thisArg) {
var T, k;
if (this == null) {
throw new TypeError("this is null or not defined");
}
var O = Object(this);
var len = O.length >>> 0;
if (typeof callback !== "function") {
throw new TypeError(callback + " is not a function");
}
if (arguments.length > 1) {
T = thisArg;
}
k = 0;
while (k < len) {
var kValue;
if (k in O) {
kValue = O[k];
callback.call(T, kValue, k, O);
}
k++;
}
};
</script>