update tenant_menu set parent_id = (select id from tenant_menu where menu_code = '6') where menu_code = '6_7';
正確語句:
update tenant_menu set parent_id = (select a.id from (select tmp.* from tenant_menu tmp) a where menu_code = '6') where menu_code = '6_7';
錯誤原因不能將這張表數據查出來之後,而後又去更新這張表,只能先建個臨時表。