Scala中List[obj]轉成json對象

使用如下方式轉換的時候，對象的屬性必須加上屬性的標籤，否則數據無法引入。 

package flinkonkafka

import com.alibaba.fastjson.JSON

import scala.beans.BeanProperty
import scala.collection.mutable.ListBuffer
object test2{
  def main(args: Array[String]) = {

    //第一種方式
    import scala.collection.mutable.ListBuffer

    val result11: result1 = result1("Sister Ma", "Yoga")
    val result12: result1 = result1("Brother Bin", "work out")
    val result13: result1 = result1("Big chenyu","jokes")

    val result1s = ListBuffer(result11, result12, result13)
    val jstr: String = JSON.toJSONString(result1s.toArray,false)
    println(jstr)


    //第2種方式
//    import org.json4s.{Formats,NoTypeHints}
//    import org.json4s.jackson.Serialization
//    import org.json4s.jackson.Serialization.write
//    // 需要添加隱式轉換
//    implicit val formats:AnyRef with Formats = Serialization.formats(NoTypeHints)
//    // 由scala對象轉換爲Json字符串
//    val dstr = write(result1s)
//    println(dstr)

  }

}


  case class result1(@BeanProperty code:String,@BeanProperty value:String)
case class datar(@BeanProperty data:Object)