PAT基礎編程題目-7-10 計算工資

PAT基礎編程題目-7-10 計算工資

題目詳情

題目地址：https://pintia.cn/problem-sets/14/problems/790

解答

C語言版

#include<stdio.h>
int main()
{
	int age, time;
	float wage;
	scanf("%d %d", &age, &time);
	if (age < 5) {  //新員工
		if (time<=40)
			wage = 30 * time;
		else
			wage = 30 * 40 + 30 * 1.5 * (time - 40);
	}
	else {  // 老員工
		if (time <= 40)
			wage = 50 * time;
		else 
			wage = 50 * 40 + 50 * 1.5 * (time - 40);
	}
	printf("%.2f", wage);
	return 0;
}

C++版

#include<iostream>
#include<iomanip>
using namespace std;
int main()
{
	int age, time;
	float wage;
	cin >> age >> time;
	if (age < 5) {  //新員工
		if (time <= 40)
			wage = 30 * time;
		else
			wage = 30 * 40 + 30 * 1.5 * (time - 40);
	}
	else {  // 老員工
		if (time <= 40)
			wage = 50 * time;
		else
			wage = 50 * 40 + 50 * 1.5 * (time - 40);
	}
	cout << fixed << setprecision(2) << wage;
	return 0;
}

Java版

import java.text.DecimalFormat;
import java.util.Scanner;
public class Main{

	public static void main(String[] args) {
		int age = 0,time = 0;
		float wage;
		Scanner scanner = new Scanner(System.in);
		if (scanner.hasNext()) {
			age = scanner.nextInt();
			time = scanner.nextInt();
		}
		scanner.close();
		if (age < 5) {  //新員工
			if (time <= 40)
				wage = 30 * time;
			else
				wage = (float) (30 * 40 + 30 * 1.5 * (time - 40));
		}
		else {  // 老員工
			if (time <= 40)
				wage = 50 * time;
			else
				wage = (float) (50 * 40 + 50 * 1.5 * (time - 40));
		}
		DecimalFormat decimalFormat = new DecimalFormat("#.00");
		System.out.println(decimalFormat.format(wage));

	}

}

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