public static int parseInt(String s, int radix)
throws NumberFormatException
{
/*
* WARNING: This method may be invoked early during VM initialization
* before IntegerCache is initialized. Care must be taken to not use
* the valueOf method.
*/
if (s == null) {//如果字符串爲空,直接拋異常
throw new NumberFormatException("null");
}
if (radix < Character.MIN_RADIX) {//如果進制小於2,拋異常
throw new NumberFormatException("radix " + radix +
" less than Character.MIN_RADIX");
}
if (radix > Character.MAX_RADIX) {//如果進制大於36,拋異常
throw new NumberFormatException("radix " + radix +
" greater than Character.MAX_RADIX");
}
int result = 0;//結果初始化爲0
boolean negative = false;//是否爲負數,默認爲false
int i = 0, len = s.length();//得到數組長度,用i來遍歷數組
int limit = -Integer.MAX_VALUE;//限制大小爲負的int最大值
int multmin;
int digit;
if (len > 0) {
char firstChar = s.charAt(0);//得到第一個字符
if (firstChar < '0') { // Possible leading "+" or "-"
if (firstChar == '-') {//如果是負數,negative賦值爲true,限制變爲int的最小值
negative = true;
limit = Integer.MIN_VALUE;
} else if (firstChar != '+')
throw NumberFormatException.forInputString(s);
if (len == 1) // Cannot have lone "+" or "-"
throw NumberFormatException.forInputString(s);
i++;//判斷完成下標+1
}
multmin = limit / radix;
/*
*multmin防止數據溢出
*如果是正數就是-2,147,483,64
*如果是負數就是-2,147,483,64
**/
while (i < len) {
// Accumulating negatively avoids surprises near MAX_VALUE
digit = Character.digit(s.charAt(i++),radix);
if (digit < 0) {
throw NumberFormatException.forInputString(s);
}
if (result < multmin) {//結果比multmin還小證明溢出了,拋異常
throw NumberFormatException.forInputString(s);
}
result *= radix;//將result擴大radix倍,integer裏面radix=10
if (result < limit + digit) {//判斷數據是否溢出
throw NumberFormatException.forInputString(s);
}
result -= digit;//因爲這裏負數正數全是先當負數算,所以是減
}
} else {
throw NumberFormatException.forInputString(s);
}
return negative ? result : -result;//如果是負數直接返回,否則返回-result即正數
}
Integer的parseInt源碼分析
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