json格式轉換與解析

將 Java 對象轉換爲 JSON 格式

private List<Person> listOfPersons = new ArrayList<Person>();
 
@Before
public void setUp() {
    listOfPersons.add(new Person(15, "John Doe", new Date()));
    listOfPersons.add(new Person(20, "Janette Doe", new Date()));
}
 
@Test
public void whenJavaList_thanConvertToJsonCorrect() {
    String jsonOutput= JSON.toJSONString(listOfPersons);
}

輸出結果：

[  
    {  
        "AGE":15,
        "DATE OF BIRTH":1468962431394,
        "FULL NAME":"John Doe"
    },
    {  
        "AGE":20,
        "DATE OF BIRTH":1468962431394,
        "FULL NAME":"Janette Doe"
    }
]