python判斷列表包含字符串

 

some_list = ['abc-123', 'def-456', 'ghi-789', 'abc-456']
if any("abcd" in s for s in some_list):
    print("asdf")


lst = ['abc-123', 'def-456', 'ghi-789', 'abc-456']
print (filter(lambda x: 'abc' in x, lst))
# print (filter(lambda x: 'abc' in x, lst)['abc-123', 'abc-456'])

 

Python判斷一個字符串是否包含子串的幾種方法

三五月兒 2016-07-31 18:29:45  144467  收藏 10
分類專欄： Python 文章標籤： string模塊 python find index count
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1.使用成員操作符 in

>>> s='nihao,shijie'
>>> t='nihao'
>>> result = t in s
>>> print result
True

2.使用string模塊的find()/rfind()方法

>>> import string
>>> s='nihao,shijie'
>>> t='nihao'
>>> result = string.find(s,t)!=-1
>>> print result
True
>>> result = string.rfind(s,t)!=-1
>>> print result
True 

3.使用string模塊的index()/rindex()方法
index()/rindex()方法跟find()/rfind()方法一樣，只不過找不到子字符串的時候會報一個ValueError異常。

import string

def find_string(s,t):
    try:
        string.index(s,t)
        return True
    except(ValueError): 
        return False

s='nihao,shijie'
t='nihao'
result = find_string(s,t)
print result  #True

4.使用字符串對象的find()/rfind()、index()/rindex()和count()方法

>>> s='nihao,shijie'
>>> t='nihao'
>>> result = s.find(t)>=0
>>> print result
True
>>> result=s.count(t)>0
>>> print result
True
>>> result=s.index(t)>=0
>>> print result
True