Hdu1718-Rank

Rank

Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 5052 Accepted Submission(s): 1978

Problem Description

Jackson wants to know his rank in the class. The professor has posted a list of student numbers and marks. Compute Jackson’s rank in class; that is, if he has the top mark(or is tied for the top mark) his rank is 1; if he has the second best mark(or is tied) his rank is 2, and so on.

Input

The input consist of several test cases. Each case begins with the student number of Jackson, an integer between 10000000 and 99999999. Following the student number are several lines, each containing a student number between 10000000 and 99999999 and a mark between 0 and 100. A line with a student number and mark of 0 terminates each test case. There are no more than 1000 students in the class, and each has a unique student number.

Output

For each test case, output a line giving Jackson’s rank in the class.

Sample Input

20070101

20070102 100

20070101 33

20070106 33

20070103 22

0 0

Sample Output

2

20070101 20070102 100 20070101 33 20070103 22 20070106 33 0 0

Sample Output

2

把類做成結構體的形式~

import java.util.Scanner;


public class Main {

	public static void main(String[] args) {
       Scanner sc = new Scanner(System.in);
       while(sc.hasNext()){
    	   String str = sc.next();
    	   Student []a = new Student[1000];
    	   int index=0;
    	   int score=0;
    	   int sum=0;
    	   while(true){
    		   String id = sc.next();
    		   int mark = sc.nextInt();
    		
    		   if(id.equals("0") && mark==0){
    			   break;
    		   }
    		    a[index++] = new Student(id,mark);
    		   if(a[index-1].id.equals(str)){
    			   score = a[index-1].mark;
    		   }
    	   }
    	 
    	   for(int i=0;i<index;i++){
    		   if(a[i].mark>score){
    			   sum++;
    		   }
    	   }
    	   System.out.println(sum+1);
       }
       
	}

}
class Student{
	public String id;
	public int mark;
	Student(String id,int mark){
		this.id=id;
		this.mark=mark;
	}
}