Who's in the Middle
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 9026 Accepted Submission(s): 4339
Given an odd number of cows N (1 <= N < 10,000) and their milk output (1..1,000,000), find the median amount of milk given such that at least half the cows give the same amount of milk or more and at least half give the same or less.
* Lines 2..N+1: Each line contains a single integer that is the milk output of one cow.
#include<cstdio>
#include<algorithm>
using namespace std;
int main()
{
int a[10005],n,i;
while(scanf("%d",&n)!=EOF)
{
for(i=0;i<n;i++)
scanf("%d",&a[i]);
sort(a,a+n);
printf("%d\n",a[n/2]);
}
return 0;
}
#include"algorithm"
#include"stdio.h"
#include"iostream"
using namespace std;
int main(int argc, char* argv[])
{
int n,a[10005],i;
//while(scanf("%d",&n)!=EOF)
while(cin>>n!=NULL)
{
for(i=0;i<n;i++)
{
cin>>a[i];
}
sort(a,a+n);
cout<<a[n/2]<<endl;
}
return 0;
}