Suspects
time limit per test2 seconds
memory limit per test256 megabytes
inputstandard input
outputstandard output
As Sherlock Holmes was investigating a crime, he identified n suspects. He knows for sure that exactly one of them committed the crime. To find out which one did it, the detective lines up the suspects and numbered them from 1 to n. After that, he asked each one: “Which one committed the crime?”. Suspect number i answered either “The crime was committed by suspect number ai”, or “Suspect number ai didn’t commit the crime”. Also, the suspect could say so about himself (ai = i).
Sherlock Holmes understood for sure that exactly m answers were the truth and all other answers were a lie. Now help him understand this: which suspect lied and which one told the truth?
Input
The first line contains two integers n and m (1 ≤ n ≤
It is guaranteed that at least one suspect exists, such that if he committed the crime, then exactly m people told the truth.
Output
Print n lines. Line number i should contain “Truth” if suspect number i has told the truth for sure. Print “Lie” if the suspect number i lied for sure and print “Not defined” if he could lie and could tell the truth, too, depending on who committed the crime.
Examples
input
1 1
+1
output
Truth
input
3 2
-1
-2
-3
output
Not defined
Not defined
Not defined
input
4 1
+2
-3
+4
-1
output
Lie
Not defined
Lie
Not defined
Note
The first sample has the single person and he confesses to the crime, and Sherlock Holmes knows that one person is telling the truth. That means that this person is telling the truth.
In the second sample there are three suspects and each one denies his guilt. Sherlock Holmes knows that only two of them are telling the truth. Any one of them can be the criminal, so we don’t know for any of them, whether this person is telling the truth or not.
In the third sample the second and the fourth suspect defend the first and the third one. But only one is telling the truth, thus, the first or the third one is the criminal. Both of them can be criminals, so the second and the fourth one can either be lying or telling the truth. The first and the third one are lying for sure as they are blaming the second and the fourth one.
題意：福爾摩斯找了n個嫌疑人，其中一個是兇手，他去調查每個人，知道這之中的m個人說的是真話，輸入中ai若爲正數，則爲第i個人說ai是兇手，若爲負數，則爲第i個人說ai不是兇手，問你其中的哪些人說謊，那些人不是說謊，哪些人的話不能確定。
解題思路：暴力討論第i個人是兇手的時候，有多少個人說的是真話，若說真話的人等於m，則i爲兇手的可能性存在，若只有這一種情況符合，則i必定爲兇手，我們即可知道一些人說的話是真是假，或者如果不等於m，則我們可以知道他肯定不是兇手，所以我們也可以知道一些人說的話是真是假，最後輸出即可。
#include<cstdio>
#define maxn 100005
int n,m,a[maxn],b[maxn],c[maxn],sum,k,d[maxn];
int main(){
scanf("%d%d",&n,&m);
for(int i=1;i<=n;i++){
scanf("%d",&a[i]);
if(a[i]>0) b[a[i]]++;
else{
c[-a[i]]++;
sum++;
}
}
for(int i=1;i<=n;i++){
if(b[i]+sum-c[i]==m){
d[i]=1;
k++;
}
}
for(int i=1;i<=n;i++){
if(a[i]>0){
if(d[a[i]]==1&&k==1) printf("Truth\n");
else if(d[a[i]]==0) printf("Lie\n");
else printf("Not defined\n");
}
else{
if(d[-a[i]]==1&&k==1) printf("Lie\n");
else if(d[-a[i]]==0) printf("Truth\n");
else printf("Not defined\n");
}
}
return 0;
}