Implement an iterator over a binary search tree (BST). Your iterator will be initialized with the root node of a BST.
Calling next()
will return the next smallest number in the BST.
Note: next()
and hasNext()
should
run in average O(1) time and uses O(h) memory, where h is the height of the tree.
/**
* Definition for binary tree
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class BSTIterator {
public:
stack<TreeNode *> s;
BSTIterator(TreeNode *root) {
pushLeft(root);
}
/** @return whether we have a next smallest number */
bool hasNext() {
return !s.empty();
}
/** @return the next smallest number */
int next() {
TreeNode *top = s.top();
s.pop();
pushLeft(top -> right);
return top -> val;
}
void pushLeft(TreeNode *root){
if(root){
s.push(root);
TreeNode *cur = root;
while(cur -> left){
s.push(cur -> left);
cur = cur -> left;
}
}
}
};
/**
* Your BSTIterator will be called like this:
* BSTIterator i = BSTIterator(root);
* while (i.hasNext()) cout << i.next();
*/