Problem L. Visual Cube

題目直通：http://acm.hdu.edu.cn/showproblem.php?pid=6330

Problem Description

Little Q likes solving math problems very much. Unluckily, however, he does not have good spatial ability. Everytime he meets a 3D geometry problem, he will struggle to draw a picture.
Now he meets a 3D geometry problem again. This time, he doesn't want to struggle any more. As a result, he turns to you for help.
Given a cube with length a, width b and height c, please write a program to display the cube.

 

 

Input

The first line of the input contains an integer T(1≤T≤50), denoting the number of test cases.
In each test case, there are 3 integers a,b,c(1≤a,b,c≤20), denoting the size of the cube.

 

 

Output

For each test case, print several lines to display the cube. See the sample output for details.

 

 

Sample Input

2 1 1 1 6 2 4

 

 

Sample Output

..+-+ ././| +-+.+ |.|/. +-+.. ....+-+-+-+-+-+-+ .../././././././| ..+-+-+-+-+-+-+.+ ./././././././|/| +-+-+-+-+-+-+.+.+ |.|.|.|.|.|.|/|/| +-+-+-+-+-+-+.+.+ |.|.|.|.|.|.|/|/| +-+-+-+-+-+-+.+.+ |.|.|.|.|.|.|/|/. +-+-+-+-+-+-+.+.. |.|.|.|.|.|.|/... +-+-+-+-+-+-+....

 

 

題解：做這題牢記八字真言：別慌 穩住  我們能贏。

#include<cstdio>
char s[1000][1000];
void init(){
    for(int i=1;i<=500;i++){
        for(int j=1;j<=500;j++){
            s[i][j]='.';

        }

    }
}
int main()
{
    int t;
    scanf("%d",&t);
    while(t--){
        init();
        int a,b,c;
        scanf("%d%d%d",&a,&b,&c);
        for(int i=1;i<=b+b+c+c+1;i++){
            if(i<=b+b){
                if(i%2==1){
                    int j;
                    for(j=b+b-i+2;j<=a+a+1+b+b-i;j++){
                        if(j%2==1)s[i][j]='+';
                        else s[i][j]='-';
                    }
                    for(;j<=a+a+1+b+b;j++){
                        if(j%2==1)s[i][j]='+';
                    }
                }else{
                    int j;
                    for(j=b+b-i+2;j<=a+a+1+b+b-i;j++){
                        if(j%2==0){
                            s[i][j]='/';
                        }
                    }
                    for(;j<=a+a+1+b+b;j++){
                        if(j%2==0){
                            s[i][j]='/';
                        }else s[i][j]='|';
                    }
                }

            }else if(i<=c+c+1){
                if(i%2==1){
                    int j;
                    for(j=1;j<=a+a;j++){
                        if(j%2==1)s[i][j]='+';
                        else s[i][j]='-';
                    }
                    for(;j<=a+a+1+b+b;j++){
                        if(j%2==1)s[i][j]='+';
                    }
                }else{
                    int j;
                    for(j=1;j<=a+a;j++){
                        if(j%2==1)s[i][j]='|';
                    }
                    for(;j<=a+a+1+b+b;j++){
                        if(j%2==1)s[i][j]='|';
                        else s[i][j]='/';
                    }
                }

            }else{
                if(i%2==1){
                    int j;
                    for(j=1;j<=a+a;j++){
                        if(j%2==0){
                            s[i][j]='-';
                        }else s[i][j]='+';
                    }
                    for(;j<=a+a+2-i+b+b+c+c;j++){
                        if(j%2==1){
                            s[i][j]='+';
                        }
                    }
                }else{
                    int j;
                    for(j=1;j<=a+a;j++){
                        if(j%2==1){
                            s[i][j]='|';
                        }
                    }
                    for(;j<=a+a+2-i+b+b+c+c;j++){
                        if(j%2==1){
                            s[i][j]='|';
                        }else{
                            s[i][j]='/';
                        }
                    }
                }
            }
        }
        int k=1;
        for(int i=(c+c+1+b+b);i>=(c+c+1);i--){
            for(int j=a+a+1+k;j<=a+a+1+b+b;j++){
                s[i][j]='.';
            }
            k++;
        }
        for(int i=1;i<=c+c+1+b+b;i++){
            for(int j=1;j<=b+b+a+a+1;j++){
                printf("%c",s[i][j]);
            }
            printf("\n");
        }
    }
    return 0;
}