math sign

∑ni=0i2=(n2+n)(2n+1)6$\sum _{i=0}^n{i}^2=\frac{(n^2+n)(2n+1)}{6}$

∑i=0ni2=ab$$\sum _{i=0}^n{i}^2=\frac{a}{b}$$

∑i=0ni2=(n2+n)(2n+1)6$$\sum _{i=0}^n{i}^2=\frac{(n^2+n)(2n+1)}{6}$$

∑j−0mj2+j3a+bc+d$$\sum _{j-0}^m{j}^2+j^3\frac{a+b}{c+d}$$

αβωΓΔΩ$$\alpha \beta \omega \mathrm{\Gamma }\mathrm{\Delta }\mathrm{\Omega }$$

x2ilog2x$$x_i^2{\log }_{2}x$$

∑i=0∞i2$$\sum _{i=0}^{\mathrm{\infty }}{i}^2$$

∏05i2$$\prod _0^5{i}^2$$

∫30$${\int }_0^3$$

limx→0$$\underset{x\to 0}{lim}$$

∞$$\mathrm{\infty }$$

∂$$\mathrm{\partial }$$

111xyzx2y2z2$$\begin{array}{ccc}1& x& x^2\\ 1& y& y^2\\ 1& z& z^2\end{array}$$

d(H1,H2)=∑i(H1(I)−H1¯)(H2(I)−H2¯)∑I(H1(I)−H1¯)2∑I(H2(I)−H2¯)2−−−−−−−−−−−−−−−−−−−−−−−−−−−−√$$d(H_1,H_2)=\frac{\sum _i(H_1(I)-\overline{H_1})(H_2(I)-\overline{H_2})}{\sqrt{\sum _I(H_1(I)-\overline{H_1}{)}^2\sum _I(H_2(I)-\overline{H_2}{)}^2}}$$