【題解】 UVA 401 迴文詞

目錄

 

題目描述

題意分析

AC代碼

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題目描述

https://vj.e949.cn/9b33ac42e5fbc32e8c88307566611887?v=1541912899

題意分析

題意：給你一個字符串，讓你判斷它是不是迴文/鏡像串

 

AC代碼

/**
* Copyright(c)
* All rights reserved.
* Author : Mingzhe
* Date : 2018-11-04-10.13.03
* Description : sample
*/
#include <cstdio>
#include <cmath>
#include <iostream>
#include <algorithm>
#include <iomanip>
#include <cstdlib>
#include <map>
#include <list>
#include <stack>
#include <queue>
#include <string>
#include <cstring>
#include <memory.h>
#define MAXN 10005
#define INF 0x3f3f3f3f
using namespace std;
typedef long long ll;

char s[100];
const char *a = "A   3  HIL JM O   2TUVWXY51SE Z  8 ";
const char *msg[] = {"not a palindrome.","a regular palindrome.", "a mirrored string.","a mirrored palindrome."};

char pend(char p){
    if(isalpha(p)) return a[p-'A'];
    else return a[p-'0'+25];
}
int main(){
    while(scanf("%s",s)!=EOF){
        int len = strlen(s),m=1,n=1;
        for(int i = 0; i < (len+1)/2; i++){
            if(s[i] != s[len-1-i]) m = 0;            //迴文判定
            if(pend(s[i]) != s[len-1-i]) n = 0;      //鏡像判定
        }
        printf("%s -- is %s\n\n", s, msg[n*2+m]);
    }
    return 0;
}