Python實現賬號密碼輸錯三次即鎖定功能簡單示例

這篇文章主要介紹了Python實現賬號密碼輸錯三次即鎖定功能,結合實例形式分析了Python文件讀取、流程控制、數據判斷等相關操作技巧,需要的朋友可以參考下

本文實例講述了Python實現賬號密碼輸錯三次即鎖定功能。分享給大家供大家參考，具體如下：

初學Python—1

#實現賬號輸錯三次即鎖定
user = "hubery"
passwd = "123"
confirm = 0
lock=0
fileOpen = open("username.txt","a+")
fileOpen.seek(0)
for i in range(3):
 username = input("username:")
 passsword = input("password:")
 for line in fileOpen.readlines():
  if username == line.strip():
   print("賬戶已經鎖定！")
   lock=1
   break
  else:
   continue
 fileOpen.seek(0)
 if user == username and lock ==0:
  if passwd == passsword:
   print("歡迎，歡迎！")
   confirm = 1
   break
  else:
   print("賬號戶或者密碼錯誤！")
   continue
 elif lock==1:
  continue
 else:
  print("1賬號或者密碼錯誤！")
  continue
fileOpen.close()
if confirm == 0 and lock==0:
 fileWrite=open("username.txt","a")
 fileWrite.write(username+"\n")
 fileWrite.close()

基本功能可以實現；

鎖定的賬號爲第三次輸錯的用戶名（待完善）

以下爲完善版本，如有錯誤，請告知

import os
user = "hubery"
passwd = "123"
count = 0
lock = 0
fileOpen = open("username.txt", "a+")
fileOpen.seek(0)
while 1:
 for i in range(5):
  username = input("username:")
  passsword = input("password:")
  for line in fileOpen.readlines():
   if username == line.strip():
    print("賬戶已經鎖定！")
    lock = 1
    break
   else:
    continue
  fileOpen.seek(0)
  if user == username:
   if lock == 1:
    continue
   elif passsword == passwd:
    print("歡迎，歡迎！")
    os._exit(0)
   elif count < 2:
    print("賬號或者密碼錯誤！")
    count += 1
    continue
   else:
    fileOpen.write(username + "\n")
    fileOpen.flush()
    print("密碼輸入錯誤超過三次，賬戶已經鎖定！")
    fileOpen.seek(0)
    continue
  else:
   print("賬號密碼錯誤！")
   continue
 check=input("還想驗證其他賬戶？（yes-繼續，no-退出）")
 if "no"==check.lower():
  os._exit(0)
 else:
  continue
fileOpen.close()

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