no String-argument constructor/factory method to deserialize from String val

https://blog.csdn.net/qq_30162239/article/details/86647164

 

解決辦法：增加一個構造函數來手動賦值

public SubmitParam(String json) throws IOException{
    SubmitParam param = new ObjectMapper().readValue(json, SubmitParam.class);
    this.id=param.getId();
    this.phoneResult = param.getPhoneResult();
    this.remark = param.getRemark();
    this.isContinue = param.getIsContinue();
    this.nextFollowUpTime = param.getNextFollowUpTime();
}

public SubmitParam(){}