d = path.dirname(__file__) #返回當前文件所在的目錄
# __file__ 爲當前文件
獲得某個路徑的父級目錄:
parent_path = os.path.dirname(d) #獲得d所在的目錄,即d的父級目錄
parent_path = os.path.dirname(parent_path) ##獲得parent_path所在的目錄即parent_path的父級目錄
獲得規範的絕對路徑:
abspath = path.abspath(d) #返回d所在目錄規範的絕對路
獲取文件路徑、文件名、後綴名的實例
def jwkj_get_filePath_fileName_fileExt(filename):
(filepath,tempfilename) = os.path.split(filename);
(shotname,extension) = os.path.splitext(tempfilename);
return filepath,shotname,extension
path=jwkj_get_filePath_fileName_fileExt(url_txt.name)[0]